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Sveta_85 [38]
2 years ago
11

Prove the identity.

Mathematics
1 answer:
EastWind [94]2 years ago
6 0

Answer:

Hi... I should do like this

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Attached solution with work.

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A boat traveled north for 28 miles, then turned x° southwest and traveled for 25 miles before stopping. When it stopped, the boa
zavuch27 [327]

Law of cosine is applicable to all the triangles. The value of the angle by which the boat turns is 39.195°.

<h3>What is the law of cosine?</h3>

Law of cosine helps us to find the third side of the triangle when 2 sides and an angle are known. It is formulated as,

c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}

a, b, c is the sides of the triangle and,

\gamma = angle opposite c

A.)

Given to us

A boat traveled north for 28 miles, then turned x° southwest and traveled for 25 miles before stopping.

When it stopped, the boat was 18 miles from its starting point.

According to the given statements, sides and angles can be written,

a = 25 miles

b = 28 miles

c = 18 miles

\theta = x^o

Substitute the values,

c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}

18=\sqrt{25^{2}+28^{2}-2(25)(28) \cdot \cos \theta}\\\\\theta = 39.195^o

Hence, the value of the angle by which the boat turns is 39.195°.

B.)

Given to us

Starting at the dock, it travels 18 miles to the left, then 25 miles up and to the right, and then 28 miles down and back to the dock.

The angle between 25 miles and 28 miles is x degrees.

According to the given statements, sides and angles can be written,

a = 25 miles

b = 28 miles

c = 18 miles

\theta = x^o

Substitute the values,

c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}

18=\sqrt{25^{2}+28^{2}-2(25)(28) \cdot \cos \theta}\\\\\theta = 39.195^o

Hence, the value of the angle by which the boat turns is 39.195°.

Learn more about the Law of cosine:

brainly.com/question/17289163

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