3 years ago

Where to put parentheses on 15\3+2•11 to make the answer 27

Mathematics

1 answer:

Allisa [31]3 years ago

6 0

Answer:

It’s 15/3+(2•11)

Step-by-step explanation:

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In the diagram, point P is a point of tangency. Find the radius r of circle O.

vlabodo [156]

Answer:

r = 12

Step-by-step explanation:

From the figure attached,

QP is a tangent to the circle O at the point P.

Therefore, by the property of tangency,

OP ⊥ QP

By applying Pythagoras theorem In right triangle QPO,

(Hypotenuse)² = (Leg 1)² + (Leg 2)²

(OQ)² = (OP)² + (PQ)²

(25 + r)² = (35)² + r²

625 + r² + 50r = 1225 + r²

50r = 1225 - 625

50r = 600

r = 12

Therefore, r = 12 units is the answer.

4 0

2 years ago

What are the solutions to this equation?

ziro4ka [17]

$\displaystyle\\(x-4)^2=49\\\\(x-4)^2-49=0\\\\(x-4)^2-7^2=0\\\\(x-4-7)(x-4+7)=0\\\\(x-11)(x+3)=0\\\\x-11 = 0~~~\text{or}~~~x+3=0\\\\x-11=0~~~\implies~~~\boxed{x_1=11}\\\\x+3=0~~~\implies~~~\boxed{x_2=-3}\\\\\boxed{\bf The~solutions~are:~~x =11~~\text{or}~~x =-3}$