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3 years ago

Given the parent function f(x) = 2^x, which graph shows f(x)+1?

Mathematics

1 answer:

Naddik [55]3 years ago

7 0

Step-by-step explanation:

f(x) + n - move the graph n units up

f(x) - n - move the graph n units down

f(x + n) - move the graph n units to the left

f(x - n) - move the graph n units to the right

====================================================

We have f(x) = 2ˣ.

g(x) = f(x) + 1 - move the graph of f(x) one unit up.

(look at the picture)

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What is the difference quotient of the function g(x) = 4^x

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Answer:

First choice

Step-by-step explanation:

The difference quotient in general is $\frac{g(x+h)-g(x)}{h}$ . To get an expression for $g(x+h)$ , replace x with x + h.

For this question,

$\frac{4^{x+h}-4^x}{h}=\frac{4^x\cdot4^h-4^x}{h}$

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3 years ago

Read 2 more answers

National statistics show that 23% of men smoke and 18.5% of women smoke. A random sample of 175 men indicated that 45 were smoke

NeTakaya

Answer:

98% C.I. = [-0.1270, 0.0994]

Step-by-step explanation:

Here

p1= proportion of men smokers

p1= 45/175= 0.2571

p2= proportion of women smokers

p2= 42/155= 0.2709

1) Choose the significance level ∝= 0.02

2) The formula for confidence interval is

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

and

(p1^- p2^) z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

3) The z value is 2.05

4) Calculations:

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(-2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=-0.1270 ( using calculator)

And

(p1^- p2^)z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=0.0994 ( using calculator)

and Putting ± 2.05 in the confidence interval formula we get limits (-0.1270, 0.0994)

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