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Mashutka [201]
3 years ago
8

What is the mass, in grams, of 122 atoms of aluminum? Round your answer to proper significant figures.

Chemistry
1 answer:
tangare [24]3 years ago
6 0

Answer:

Mass = 547.02 × 10⁻²³g

Explanation:

Given data:

Number of atoms of Al = 122 atom

Mass in gram = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

122 atom/6.022 × 10²³ atoms ×  1 mol

20.26× 10⁻²³ mol

Mass in gram:

Mass = number of moles  × molar mass

Mass = 20.26× 10⁻²³ mol  × 27 g/mol

Mass = 547.02 × 10⁻²³g

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Answer:

Nuclear fusion is when two atomic nuclei combine and form one nucleus. Nuclear fusion generates all of the Sun's energy. Inward pulling by the Sun's gravity is counteracted by outward pushing by the Sun's nuclear fusion; this balance keeps the sun from collapsing or exploding.

Explanation:

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How does changing temperature affect the solubility of gases in liquids?
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Which has more calories: table sugar or aspartame?
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Predict the order of acid strengths in the following series of cationic
stich3 [128]

Answer:

CH3CH=NH2+>CH3CH2NH3+

Explanation:

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3 years ago
Please help asap 18 points if help and right answer please ​
barxatty [35]

Answer:

Lithium = 8%

Bromine = 92%

Explanation:

To calculate percent composition, you must:

- Calculate the molar mass.

- Divide the subtotal for each element's mass by the molar mass.

- Convert to a percentage

With that being said, given LiBr (Lithium Bromide), calculate the molar mass:

Lithium has an atomic weight of 7, and there is one Lithium atoms in LiBr. Bromine has an atomic weight of 80, and there is one Bromine atom in LiBr:

1(7)\\1(80)

Add the two products:

80+7

=87

The molar mass of LiBr is about 87 grams.

With that information, divide the subtotal of Lithium by the molar mass, and then multiply by 100 to convert to a percentage:

\frac{7}{87} × 100=

8.0459%

(Round to nearest percentage):

8%

Therefore, the percent composition of Lithium in the compound Lithium Bromide is about 8%.

Now, divide the subtotal of Bromine by the molar mass, and then multiply by 100 to convert to a percentage:

\frac{80}{87} × 100=

91.9540

(Round):

92%

Therefore, the percent composition of Bromine in the compound Lithium Bromide is about 92%.

6 0
3 years ago
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