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lesya [120]
3 years ago
13

Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the pipi

ng. However, consider a pipe where water was allowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change, (ΔT), of the water if 180.5 g of water sat in the copper pipe from part A, releasing 2494 J of energy to the pipe? The specific heat of water is 4.184 (J/g)⋅∘C.
Chemistry
1 answer:
Aleksandr [31]3 years ago
6 0

Answer: -

3.3° C

Explanation: -

Mass of water m = 180.5 g

Energy released as heat Q = 2494 J

Specific heat is defined as the heat required to raise the temperature of the unit mass of a given substance by 1 C.

Specific heat of water Cp = 4.184 (J/g)⋅∘C

Using the formula

Q = m x Cp x ΔT

We get temperature change ΔT = Q / (m x Cp)

= 2494 J / ( 180.5 g x 4.184 (J/g)⋅∘C

= 3.3° C

Thus the temprature change, (ΔT), of the wateris 3.3 °C if 180.5 g of water sat in the copper pipe from part A, releasing 2494 J of energy to the pipe

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The effective nuclear charge is the amount of charge experienced by an electron taking into account any shielding effects from o
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Answer:

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Explanation:

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Carbon- 1s2 2s2 2p2

Moving from boron to carbon, the effective nuclear charge increases without a corresponding increase in the number of shells. Remember that shielding increases with increase in the number of intervening shells between the outermost electron and the nucleus. Since there isn't an increase in shells, boron experience a lower screening effect.

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3 years ago
The vapor pressure of water at 25.0°C is 23.8 torr. Determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
mrs_skeptik [129]

According to Raoult's law the relative lowering of vapour pressure of a solution made by dissolving non volatile solute is equal to the mole fraction of the non volatile solute dissolved.

the relative lowering of vapour pressure is the ratio of lowering of vapour pressure and vapour pressure of pure solvent

\frac{p^{0-}p}{p^{0}}=x_{B}

Where

xB = mole fraction of solute=?

p^{0}=23.8torr

p = 22.8 torr

x_{B}=\frac{23.8-22.8}{23.8}=0.042

mole fraction is ratio of moles of solute and total moles of solute and solvent

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mass of glucose = moles X molar mass = 1.218 X 180 = 219.24 grams



3 0
3 years ago
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