Answer:
2.35 L
Explanation:
Given data:
Mass of sodium metal = 4.81 g
Volume of Cl react at STP= ?
Balance chemical equation = ?
Solution:
Balance chemical equation:
2Na + Cl₂ → 2NaCl
Number of moles of Na:
Number of moles = mass/ molar mass
Number of moles = 4.81 g/ 23 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of sodium and chlorine from balance chemical equation.
Na : Cl₂
2 : 1
0.21 : 1/2×0.21 = 0.105 mol
Volume of Cl₂:
PV = nRT
standard temperature = 273 K
standard pressure = 1 atm
R = general gas constant = 0.0821 atm.L/mol.K
n = moles = 0.105 mol
Now we will put the values.
V = 0.105 mol × 0.0821 atm.L/mol.K × 273 K / 1 atm
V = 2.35 L/ 1
V = 2.35 L
Answer:
Fe2O3, Fe2S3 and FeCl3
Explanation:
The formular shows the number of atoms of element present in the compound. The number of atoms in turn depends on the charges. The goal is to have a neutral compound with oxidation number of zero.
Oxide:
Iron(Fe) has oxidation number (O.N) of +3, oxygen has O.N of -2. The formular with a balanced (Charge = 0) O.N number is; Fe2O3
Sulphide:
Iron(Fe) has oxidation number (O.N) of +3, sulphur has O.N of -2. The formular with a balanced (Charge = 0) O.N number is; Fe2S3
Chloride:
Iron(Fe) has oxidation number (O.N) of +3, chlorine has O.N of -1. The formular with a balanced (Charge = 0) O.N number is; FeCl3
