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Naya [18.7K]
3 years ago
9

Rema purchased 18 ounces of gold in 2005 for $414 per ounce in order to try to diversify her investment portfolio. She sold a th

ird of her holdings in gold in 2009 at a price $953 per ounce. She sold the rest of her gold holdings in 2010 for $1,367 per ounce.
What is Prema’s profit in 2009 and 2010?
Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0

Given :

Rema purchased 18 ounces of gold in 2005 for $414 per ounce in order to try to diversify her investment portfolio.

She sold a third of her holdings in gold in 2009 at a price $953 per ounce. She sold the rest of her gold holdings in 2010 for $1,367 per ounce.

To Find :

What is Prema’s profit in 2009 and 2010.

Solution :

Price of one third ounces of gold, in 2005 is :

P = $414/3 = $138 .

Profit from selling them in 2009 is :

P1 = $(953 - 138) = $815 .

Profit from selling them in 2010 is :

P2 = $( 1367 - ( 414 - 138 ) ) = $1091 .

Therefore, Prema's profit in 2009 is $815 and 2010 is $1091.

Hence, this is the required solution.

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cupoosta [38]

Answer:

The height of rectangle is 5 inches

Step-by-step explanation:

<u><em>The correct question is</em></u>

A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, Find the height

Let

x -----> the width of the rectangle in inches

y ----> the height of the rectangle in inches

d ---> diagonal measurement of the rectangle in inches

we know that

Applying the Pythagorean Theorem

d^2=x^{2}+y^{2}

we have

d=13\ in

so

13^2=x^{2}+y^{2}

169=x^{2}+y^{2} ----> equation A

x=y+7 ---> equation B

substitute equation B in equation A

169=(y+7)^{2}+y^{2}

solve for y

169=y^2+14y+49+y^{2}

2y^2+14y+49-169=0

2y^2+14y-120=0

solve the quadratic equation by graphing

using a graphing tool

The solution is y=5

see the attached figure

therefore

The height of rectangle is 5 inches

5 0
3 years ago
Micah pays 54$ for an item originally priced 60$. What percentage of the original price was his discount?
pantera1 [17]

Answer: The percentage of the original price was his discount = 10%

Step-by-step explanation:

Given: original price = $60

Price after discount =  $54

Discount = Price after discount  - original price

= $ (60-54) = $6

The percentage of the original price was his discount = \dfrac{Discount}{Original\ price}\times100

=\dfrac{6}{60}\times100\%\\\\=\dfrac{1}{10}\times100\%\\\\=10\%

Hence, the percentage of the original price was his discount = 10%

3 0
3 years ago
15 POINTS-
Doss [256]
I think it’s $3.55
I think this because if u subtract 2.45- 45% = 1.10 sooo u will have to add $1.10 to 2.25 and that will add up the 45% that Walmart is paying with the original price.
8 0
3 years ago
A research company desires to know the mean consumption of meat per week among people over age 40. A sample of 610 people over a
Papessa [141]

Answer: (3.0,\ 3.2)

Step-by-step explanation:

Confidence interval for population mean is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}  (1)

, where \overline{x} = Sample mean

z_{\alpha/2}= Critical z-value

\sigma = Population standard deviation.

n= Sample size.

As per given , we have

n= 610

\sigma=1.1

\overline{x}=3.1

Significance level for 85% confidence : \alpha=1-0.85=0.15

By z-table critical two tailed z-value : z_{\alpha/2}=z_{0.075}=1.44

Put all values in (1) , we get

3.1\pm 1.44\dfrac{1.1}{\sqrt{610}}

3.1\pm 1.44\dfrac{1.1}{24.698}

3.1\pm 0.064

=(3.1-0.064,\ 3.1+0.064)=(3.036,\ 3.164)\approx(3.0,\ 3.2)

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5 0
4 years ago
A manufacturer of pickup trucks is required to recall all the trucks manufactured in a given year for the repair of possible def
Crank

Answer: 2%

Step-by-step explanation:

Let A be the event of having defective steering and B be the vent of having defective brake linings.

Given: P(A)  = 0.03  P(B) = 0.05

P(neither A nor B ) = 0.94

Using formula: P(either A nor B) = 1- P(neither A nor B )

= 1-0.94

i.e.  P(either A nor B) =0.06

Using formula:P(A and B) = P(A)+P(B)-P(either A or B)

P(A and B) =0.03+0.05-0.06

= 0.02

Hence, the percentage of the trucks have both defects = 2%

8 0
3 years ago
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