Hi!!!!!!!!!!!!
Hope I help!
SO the correct answer are...............................
<h2><u>
0=0! 1=4! 2=8! 3=12! 4=16! &, 5=20!!!!!!!!!!</u></h2>
Answer:
D. 62 square feet
Step-by-step explanation:
uz + wx + (v+z)(y-u-w)
6*3 + 4*6 + (7+3)(12-6-4)
18 + 24 + 20 = 62
Answer:
First, a absolute value function is something like:
y = f(x) = IxI
remember how this work:
if x ≥ 0, IxI = x
if x ≤ 0, IxI = -x
Notice that I0I = 0.
And the range of this function is all the possible values of y.
For example for the parent function IxI, the range will be all the positive reals and the zero.
First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.
Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:
y ≥ A
Or all the real values equal to or larger than A.
if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:
y ≤ A
Or "All the real values equal to or smaller than A"
Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3.
<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>
<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>
<span>(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) </span>
<span>==> x/6 = (3√3 - h)/(3√3) </span>
<span>==> x = (6√3 - 2h)/√3 </span>
<span>Thus, the area of the upper triangle is: </span>
<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>
<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>
<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>
<span>Solving with the Quadratic Formula gives: </span>
<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>
<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>
<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>
<span>I hope this helps! ^^ Brainliest Please?</span><span>
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