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PilotLPTM [1.2K]
3 years ago
6

HELP. WILL GIVE POINTS ASAP

Mathematics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

b and c i think

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It is possible none of the choices is the solution?
velikii [3]

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Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution,
Gnom [1K]

Answer:

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Step-by-step explanation:

\left[\begin{array}{ccc|c}1&0&-3&-5\\3&1&2&4\\2&2&1&7\end{array}\right]

you can do linear combination between the rows:

2nd row=R2-3R1 and 3th row=R3-2R1

\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&2&7&17\end{array}\right]

3th row=(3R2-R3)/15

\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&0&1&\frac{7}{5} \end{array}\right]

1st row=R1+3R3 and R2-11R3

\left[\begin{array}{ccc|c}1&0&0&-4/5 \\0&1&0&18/5 \\0&0&1&7/5\end{array}\right]

x1=-4/5, x2=18/5 and x3=7/5

6 0
3 years ago
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