Each van carries 13 students and each bus carries 25 students.
<h3><u>Distribution</u></h3>
Given that the senior class at High School A and the senior class at High School B both planned trips to Yellowstone, and the senior class at High School A rented and filled 5 vans and 2 buses with 115 students, while High School B rented and filled 1 van and 6 buses with 163 students, and each van carried the same number of students and each bus carried the same number of students, to determine the number of students in each van and in each bus, the following calculation must be made:
- 5X + 2Y = 115
- 1X + 6Y = 163
- 5X + 2Y = 115
- 5X + 30Y = 815
- 815 - 115 = 28Y
- 700 = 28Y
- Y = 700 / 28
- y = 25
- 1X + 6x25 = 163
- 1X = 163 - 150
- X = 13
Therefore, each van carries 13 students and each bus carries 25 students.
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Answer:
see attached
Step-by-step explanation:
graph y = -3/2x - 2
x Intercept: 0 = -3/2x -2
3/2x = -2
x = <u>-2 (2)</u>
3
x = -4/3
(-4/3, 0)
y intercept: (0, -2)
Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))
Let A = arcsin(-5/13) = -arcsin(5/13)
Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12
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The answer would be 200,000.
This is because you go to the hundred thousands' place and look one place to the right. Since there is a 6 and 6>5 you round up to 2 making it 200,000. Hope this helps!