All categories

2 years ago

A paper company needs to ship paper to a large printing business. The paper will be

Mathematics

1 answer:

Nikolay [14]2 years ago

6 0

Answer:

Small boxes: 8

Large boxes: 11

Step-by-step explanation:

number of small boxes = x

number of large boxes = y

weight of boxes is represented by:

50x + 80y = 1280

Number of boxes is represented by:

x + y = 19

First, we'll solve for x in terms of y:

x = 19-y

Then we'll substitute that into the weight equation

50(19-y) + 80y = 1280

950 - 50y + 80y = 1280

30y = 330

y = 11

Now drop that numerical value into the number of boxes equation, and we'll get

x + 11 = 19

x = 8

Check the math in the weight equation:

50(8) + 80(11) =

400 + 880 = 1280

Let me know if you have any questions. Have a good evening!

You might be interested in

Choose the correct response

lilavasa [31]

Answer:

f(2) = 9

Step-by-step explanation:

It's give in the question,

Two different functions are,

f(x) = 4x + 1

g(x) = -2x

Then we have to find the output value of function 'f' for the input value x = 2.

By substituting the value of x in the function 'f',

f(2) = 4(2) + 1

= 9

f(2) = 9

5 0

2 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago

It takes 2 hours to drive 80 miles and 4 hours to drive 160 miles. Find the rate of change. I need this asap

natita [175]

Answer:

40 miles per hour

Step-by-step explanation:

80 divided by 2 is 40

160 divided by 4 is 40

5 0

3 years ago

What is the value of the expression i0•i1•i2•i3•i4

My name is Ann [436]

$\bf \stackrel{1}{i^0}\cdot \stackrel{i}{i^1}\cdot \stackrel{-1}{i^2}\cdot \stackrel{-i}{i^3}\cdot \stackrel{1}{i^4}\implies i\cdot i\cdot 1\implies i^2\implies -1$

8 0

3 years ago

Read 2 more answers

If $25, 000 is invested into an account paying 4.5% per year, compounded quarterly, how much money can be withdrawn from the acc

pogonyaev

The money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

<h3>What is compound interest?</h3>

The formula for compound interest is given as;

$A = P ( 1 + \frac{r}{n} )^n^t$

P = principal interest = $25, 000

r = rate = 4. 5%

n = 2 months

t = 6 years

A = $25, 000 ( 1 + \frac{4. 5}{2} )^2 ^*^6$

A = $25, 000(1 + 0. 75)^1^2$

A = $25, 000( 825. 00)$

A = $20, 625, 000

Thus, the money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

Learn more about compound interest here:

brainly.com/question/2455673

#SPJ1

7 0

2 years ago