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lapo4ka [179]
3 years ago
14

A system of equations is shown below: y = 8x − 2 y = 9x − 7 What is the solution to the system of equations? (1 point) (−5, 38)

(−5, −38) (5, 38) (5, −38)
Mathematics
1 answer:
Oxana [17]3 years ago
4 0

Answer:

(5,38)

Step-by-step explanation:

Use graphing calculator and the answer should be the point where the line crosses each other.

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When constructing an inscribed regular hexagon, what steps come after six arcs are created on the circle? Connect every other in
Amiraneli [1.4K]

Answer:

b i think

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The measure of RST can be represented by the expression (6x + 12)°.
Valentin [98]

Answer:

The measure of angle RST is 120\°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m -----> equation A

m -----> equation B

equate equation A and equation B

(6x+12)\°=78\°+(3x-12)\°

6x-3x=78\°-24\°

3x=54\°

x=18\°

The measure of angle RST is equal to

m

8 0
3 years ago
Read 2 more answers
Geometry. Very basic.
AveGali [126]

Answer:

A)10.25 cm ; B)5 square cm  

Step-by-step explanation:

A)

Formula:

p=(a+b+c)         [p= perimeter ;  a,b , and c are the side lengths.]

∴The perimeter of the triangle =(4+2.75+3.5) cm  

                                                =10.25 cm

B)

Formula:

A = 1/2 . b .h    [A=area ; b= base ; h= height]

∴The area of the triangle = (1/2 . 4 . 2.5) square cm    [b=4 ; h=2.5]

                                         =5 square cm  

6 0
3 years ago
What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
3 years ago
Read 2 more answers
What is a 2c − 5b − c a − b simplified?
timama [110]
All you have to do is combine like terms. 2c and (-c) are like terms (-5b) and (-b) are like terms and a is a term. So, 2c combined with (-c) is C. (-5b) and (-b) combined is (-6b). Since a doesnt need to be combined with anything, you leave it as it is so your answer will then be c - 6b + a (this is the answer assuming that there is a + in front of the a. If there is a - sign, then just change your +a to -a at the end
7 0
3 years ago
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