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3 years ago

I need help with mathematics work ? Anyone please

Mathematics

2 answers:

Masteriza [31]3 years ago

5 0

If you have any questions, don’t be afraid to ask!

arlik [135]3 years ago

4 0

Answer:

four days

Step-by-step explanation:

if you times 400 by ten you get 4,000, so then you have to divide by 1,000 and you get 4

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FIRST ANSWER GETS BRANLIEST!!

Mashcka [7]

Answer:

(0,0)

Step-by-step explanation:

Let's think about how the graph of this would look.

We know that y will be $x^2$ , meaning that if x was 0, y would be 0.

If x was 1, y would be 1

If x was 2, y would be 4.

Now let's think about negative numbers.

If x was -1, y would be 1 (since $-1^2 = 1$

If x was -2, y would be 4 (since $-2^2 = 4$ ).

This means that our graph would turn at the point where x and y are equal (excluding 1,1)

This is 0,0.

So 0,0 is the turning point of this graph.

Hope this helped!

3 0

2 years ago

Please help me out with this

AURORKA [14]

6m (m+2) = 0 is the factored form
m=0, m=-2 is m

Steps are on paper
If you need more explanation, comment

4 0

2 years ago

Miss stephens is buying pencils for all of her students,she already has 7 pencils,and needs a total of 59. If they come in packs

svp [43]

Answer:

Step-by-step explanation:

13 x 4 = 52 + 7 = 59

4 0

2 years ago

Write the equation of the line graphed below in Point-Slope form. Use the point labeled on the graph. State the slope and point.

saw5 [17]

Given:

The graph of a line.

To find:

The point-slope form of the given line.

Solution:

From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{-1-5}{0-1}$

$m=\dfrac{-6}{-1}$

$m=6$

The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:

$y-y_1=m(x-x_1)$

$y-5=6(x-1)$

Therefore, the point-slope form is $y-5=6(x-1)$ , slope is 6 and the point is (1,5).

6 0

3 years ago

* The nth term of sequence A is 3n − 2 The nth term of sequence B is 10 − 2n Sally says there is only one number that is in both

Nina [5.8K]

Answer:

Sally is not right

Step-by-step explanation:

Given the two sequences which have their respective $n^{th}$ terms as following:

Sequence A. $3n - 2$

Sequence B. $10 - 2n$

As per Sally, there exists only one number which is in both the sequences.

To find:

Whether Sally is correct or not.

Solution:

For Sally to be correct, we need to put the $n^{th}$ terms of the respective sequences as equal and let us verify that.

$3n-2=10-2n\\\Rightarrow 3n+2n=10+2\\\Rightarrow 5n=12\\\Rightarrow n = \dfrac{12}{5}$

When we talk about $n^{th}$ terms, $n$ here is a whole number not a fractional number.

But as per the statement as stated by Sally $n$ is a fractional number, only then the two sequences can have a number which is in the both sequences.

Therefore, no number can be in both the sequences A and B.

Hence, Sally is not right.

7 0

2 years ago