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AnnyKZ [126]
3 years ago
13

Car Survey in a survey of 1,800 people who owned a certain type of car, 1,080 said they would buy

Mathematics
1 answer:
noname [10]3 years ago
8 0

Answer: 60%

Step-by-step explanation:

First you have 1,080 satisfied out of 1,800.

Then you divide 1,080/ 1,800.

When you divide you get .6

Finally move the decimal 2 places to the right and you get 60 which is 60%.

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Enter the slope of the line through the points (4 , 15) and (4 , 12)​
pentagon [3]

Answer:

Step-by-step explanation:

slope m= (y2-y1) / (x2-x1) = 15-12 / 4-4 = 3/0 is undefined since we can not divide by 0

slope is undefined so the line is vertical

7 0
2 years ago
Read 2 more answers
A salesman's commission on 150,000 sale is 3000. what is the percent?
fomenos
The percentage is 98%.

You can find this by multiplying 98% (0.98) and 150,000 to get 147,000. Then subtract 147,000 from 150,000 to get 3,000.

I hope this helps!
8 0
3 years ago
What is the area of the trapezoid
topjm [15]

Answer:

24 in

Step-by-step explanation:

Add up all the inches. voila!

5 0
3 years ago
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Prove that it is impossible to dissect a cube into finitely many cubes, no two of which are the same size.
solniwko [45]

explanation:

The sides of a cube are squares, and they are covered by the respective sides of the cubes covering that side of the big cube. If we can show that a sqaure cannot be descomposed in squares of different sides, then we are done.

We cover the bottom side of that square with the bottom side of smaller squares. Above each square there is at least one square. Those squares have different heights, and they can have more or less (but not equal) height than the square they have below.

There is one square, lets call it A, that has minimum height among the squares that cover the bottom line, a bigger sqaure cannot fit above A because it would overlap with A's neighbours, so the selected square, lets call it B, should have less height than A itself.

There should be a 'hole' between B and at least one of A's neighbours, this hole is a rectangle with height equal to B's height. Since we cant use squares of similar sizes, we need at least 2 squares covering the 'hole', or a big sqaure that will form another hole above B, making this problem inifnite. If we use 2 or more squares, those sqaures height's combined should be at least equal than the height of B. Lets call C the small square that is next to B and above A in the 'hole'. C has even less height than B (otherwise, C would form the 'hole' above B as we described before). There are 2 possibilities:

  • C has similar size than the difference between A and B
  • C has smaller size than the difference between A and B

If the second case would be true, next to C and above A there should be another 'hole', making this problem infinite. Assuming the first case is true, then C would fit perfectly above A and between B and A's neighborhood.  Leaving a small rectangle above it that was part of the original hole.

That small rectangle has base length similar than the sides of C, so it cant be covered by a single square. The small sqaure you would use to cover that rectangle that is above to C and next to B, lets call it D, would leave another 'hole' above C and between D and A's neighborhood.

As you can see, this problem recursively forces you to use smaller and smaller squares, to a never end. You cant cover a sqaure with a finite number of squares and, as a result, you cant cover a cube with finite cubes.

3 0
3 years ago
Please help me asap !!
Natasha2012 [34]

Answer:

3.5

Step-by-step explanation:

(42 - 14)/(12 - 4) = 28/8 = 7/2 = 3.5

5 0
2 years ago
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