Divide:
( 8x^4 - 3x^2 + x - 10) by ( x - 1 ) ============================> 8x^5 − 8x^4 − 3x^3 + 4x^2 − 11x +10
Simplify:
(8x^4 − 3x^2 + x − 10)(x − 1)
(8x^4 + −3x^2 + x + −10)(x + −1)
(8x^4)(x) + (8x^4)(−1) +(−3x^2)(x) + (−3x^2)(−1) + (x)(x) + (x)(−1) + (−10)(x) +(−10)(−1)
8x^5 − 8x^4 −3x^3 + 3x^2 + x^2 − x − 10x +10
Hence, Your Answer, =====> 8x^5 − 8x^4 − 3x^3 + 4x^2 − 11x + 10
Hope that helps!!!! : )
Answer:
S= 4000n+50000
Step-by-step explanation: Table
50000+4000=54000 0 5000
54000+4000=58000 1 54000
58000+4000=62000 etc.. 2 58000
3 62000
Is increasing by 4000 and thats the rate of change so S=4000n
And the y intercept always will be with a 0 in the cordinates and the only with a 0 is 50000.
We put all together and it will be
Answer: S=4000n+50000
I'm going to assume that you meant the following:
(x-1)
---------------
x^2-3x+2
Factoring the denominator, we get:
(x-1)
------------
(x-1)(x-2)
Notice that we have x-1 in both the numerator and the denominator. This factor cancels. HOWEVER: x can still not equal 1, which would lead to div. by zero. With the factor x-1 cancelled, we have 1 / (x-2). As x approaches 1 from either side, y approaches 1 / (1-2), or 1 / (-1), or -1. Thus, the limit exists and is -1.
Answer:
The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.
Step-by-step explanation:
The amount of water in the tank after 15 days is given by the series
910+(−710)+810+(−610)+⋯+310+(−110)+210
From the series, we can observe that, if water is added for a particular day then water will be drained the following day.
Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.
Hence, we can complete the series thus:
910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210
To evaluate this, we get
910-710+810-610+710-510+610-410+510-310+410-210+310-110+210
= 1610.0 gallons
Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.
7. compound events that that are not affected by other's outcomes
