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3 years ago

Write an equation of the line that passes through (2, -5) and is parallel to the line 2y = 3x + 10.

Mathematics

1 answer:

Leto [7]3 years ago

8 0

Answer:

Use the given slope and point to substitute into the point-slope formula y−y1=m(x−x1).

Slope-intercept form:

y=3x²+4x−25

Point-slope form:

y+5=(3x+10)⋅(x−2)

Step-by-step explanation:

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Zigmanuir [339]

32000 is your answer

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3 years ago

What is the answer to 2b + 8- 5b + 3 = -13 + 8b - 5

Alborosie

Answer:

2 8/11 = b

Step-by-step explanation:

2b + 8 - 5b + 3 = -13 + 8b - 5

combine like terms

11 - 3b = -18 + 8b

add 3b

11 = -18 + 11b

add 18

29 = 11b

divide by 11

2 8/11 = b

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3 years ago

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The answer is A

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3 years ago

Equation of the line contains the points (-3,2) and (5,-5)

makkiz [27]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:

$(x_ {1}, y_ {1}): (- 3,2)\\(x_ {2}, y_ {2}) :( 5, -5)$

So the slope is:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-5-2} {5 - (- 3)} = \frac {-7} {5 + 3} = - \frac {7} {8}$

Thus, the equation of the line is of the form:

$y = - \frac {7} {8} x + b$

We substitute one of the points and find "b":

$2 = - \frac {7} {8} (- 3) + b\\2 = \frac {21} {8} + b\\b = 2- \frac {21} {8}\\b = \frac {16-21} {8}\\b = - \frac {5} {8}$

Finally, the equation is:

$y = - \frac {7} {8} x- \frac {5} {8}$

Answer:

$y = - \frac {7} {8} x- \frac {5} {8}$

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3 years ago

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Over [174]

Step-by-step explanation:

Please I can't get the question well.Can you please write the words fully?

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3 years ago