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Leno4ka [110]
3 years ago
10

Use the drop-down menus to complete each equation so the statement about its solution is true?

Mathematics
1 answer:
SashulF [63]3 years ago
7 0

5 - 4 + 7x + 1 = 7x + (5 - 4 + 1) = 7x + 2


NO SOLUTIONS:

<em>5 - 4 + 7x + 1 = 7x + a    </em><em>(a - any real number, except 2)</em>


ONE SOLUTION:

<em>5 - 4 + 7x + 1 = bx + c     </em><em>(b - any real number, except 7, c - any real number)</em>


INFINITELY MANY SOLUTIONS:

<em>5 - 4 + 7x + 1 = 7x + 2</em>


Examples:

2x + 3 = 2x + 5     <em>subtract 2x from both sides</em>

3 = 5    FALSE      <em>(NO SOLUTIONS)</em>


2x + 3 = x - 4      <em>subtract x from both sides</em>

x + 3 = -4       <em>subtract 3 from both sides</em>

x = -7          (<em>ONE SOLUTION)</em>


2x + 3 = 2x + 3      <em>subtract 2x from both sides</em>

3 = 3     TRUE      <em>(INFINITELY MANY SOLUTIONS)</em>

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Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

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