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stealth61 [152]

2 years ago

12

The Police station records how many cars passed through a particular intersection for 5 consecutive days decide of a stop light

needed to be installed.The data will be recorded on table of cars passing each day.Is the data continuous or discrete data?

1 answer:

Ivenika [448]2 years ago

7 0

The data is continuous

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The temperature for 5 days is shown in the table. If on the 6th day the temperature is 83, by how much will this increase the ov

laila [671]

Answer:

I cant see the table

Step-by-step explanation:

4 0

2 years ago

What is the area of this figure? Enter your answer in the box.

Paladinen [302]

The area would be 35 cm squared.

Lets break it down:
Triangle- The area of a triangle is base×height÷2
so if we plug in the numbers, the base would be 5 (the length) and the height would be 4 (the height). 5×4= 20÷2= 10.
Square- The area of a square is base×height so if we pluged in the numbers, the base is 5 (the length) and the height is 5 (the height). 5×5= 25.

10+25= 35 cm squared

Hope this helps!

6 0

3 years ago

A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr

ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so $\pi = 0.30$

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so $n = 10$

We want to find P(X = 1). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211$

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is $P(X > 1)$

We have that:

$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

We also have that:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282$

So

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493$

Finally

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507$

There is a 85.07% probability that more than 1 has the marker.

3 0

3 years ago

I need help :)<br> Find the GCF: 10x^5−16x^4+4x^2

andreev551 [17]

The greatest common factor is 2x^2.
the largest number that divides evenly into <span>10x^5−16x^4+4x^2 is two.
the highest degree is x^2 so the answer would be 2x^2
</span>

5 0

3 years ago

What is the value of 6/1+i?

just olya [345]

Answer:

6/1+i= 6 + i

Step-by-step explanation:

6 0

3 years ago