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stealth61 [152]
2 years ago
12

The Police station records how many cars passed through a particular intersection for 5 consecutive days decide of a stop light

needed to be installed.The data will be recorded on table of cars passing each day.Is the data continuous or discrete data?
​
Mathematics
1 answer:
Ivenika [448]2 years ago
7 0
The data is continuous
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What do scientists usually do if they can't draw clear conclusions?
Dmitry_Shevchenko [17]

Answer:

<em>B. collect more data to support their hypothesis.</em>

<em>D. something the data do not directly show, but that can be found indirectly.</em>

<em>A. agree with the hypothesis.</em>

Step-by-step explanation:

8 0
3 years ago
Please help, I really desperate
Paladinen [302]

Answer:

V candle ≈ 196.9 cm³

Step-by-step explanation:

Volume of cone = ( π·r²·h)/3

V candle = V big cone -V small cone

V candle = [ π·4²·(8+5) - π·2²·5]/3

V candle = ( π·16·13 - π·4·5)/3

V candle = (π·16·13 - π·4·5)/3

V candle = π·(208 - 20)/3

V candle = π·188/3

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V candle ≈ 196.9 cm³

8 0
2 years ago
Which graph represents the sequence: 1/2, 1, 2, 4, 8...?
Aleonysh [2.5K]

The graph represents the sequence is Option D.

<h3>Further explanation </h3>

A function defined in the set of natural numbers is called a sequence.

Allow \boxed{a_n \ as \ n^{th} \ term}, or general term.

In a sequence, n should always represent a natural number, i.e.,

n > 0, n = 1, 2, 3, ...,

but the value of \boxed{a_n} may be any real number depending on the formula for the general term of the sequence.

A sequence is considered geometric if the ratio between each consecutive term is common.  

In our problem, the sequence is \boxed{ \ \frac{1}{2}, 1, 2, 4, 8, ... \ }

The ratio of each term \boxed{a_{n+1}} to the previous term \boxed{a_n} is equal 2, so we can formalize the sequence as

\boxed{\frac{a_{n+1}}{a_n} =2}.

The consecutive terms of the sequence have a common ratio r = 2, so this sequence is geometric.

The general term of a geometric sequence \boxed{a_n} with common ratio r is \boxed{\boxed{ \ a_n = a_1 \cdot r^{n-1} \ }}.

Presently we go back to the question. The graph shows the horizontal axis as n and the vertical axis is the general term \boxed{a_n}. The relationship between n, the terms, and the coordinates as written below:

\boxed{n = 1 \rightarrow the \ 1st \ term \ a_1 = \frac{1}{2} \rightarrow \bigg( 1, \frac{1}{2} \bigg)}

\boxed{n = 2 \rightarrow the \ 2nd \ term \ a_2 = 1 \rightarrow (2, 1)}

\boxed{n = 3 \rightarrow the \ 3rd \ term \ a_3 = 2 \rightarrow (3, 2)}

\boxed{n = 4 \rightarrow the \ 4th \ term \ a_4 = 4 \rightarrow (4, 4)}

\boxed{n = 5 \rightarrow the \ 5th \ term \ a_5 = 8 \rightarrow (5, 8)}

Therefore, the graph representing the sequence is Option D.

<u>Note:</u>

  • The general term of a geometric sequence is exponential.
  • From the common ratio (r > 1) and graph, the type is an increasing sequence.
<h3>Learn more </h3>
  1. Combining two functions to create a geometric sequence brainly.com/question/1695742
  2. A word problem about arithmetic and geometric sequences brainly.com/question/3395975
  3. Drawing graph of the geometric sequence brainly.com/question/3166290

Keywords: which, the graph, geometric sequences, common ratio, general term formula, natural numbers, The consecutive terms, arithmetic

6 0
3 years ago
What is the solution to the system of equations below?
Pachacha [2.7K]

Answer:

(-8, 2)

Step-by-step explanation:

set these equations equal to each other

1/2x + 6 = -3/4x -4

5/4 x = -10

x = -10x4/5 = -40/5 = -8

plug this x into one of the equations

y = 1/2 (-8) + 6

y = -4 + 6

y = 2

6 0
3 years ago
Find the first term and common difference of an AP, whose 7th term is 29/6 and 15th term is 11/2.​
777dan777 [17]

Answer:

The first term is 13/3 and the common difference is d = 1/12

The formula is a(n) = 13/3 + (1/12)(n - 1)        

Step-by-step explanation:

The general equation for an arithmetic progression is:

a(n) = a(1) + d(n - 1), where d is the common difference/

Case 1:  n = 7:  29/6 = a(1) + d(7 - 1), or 29/6 = a(1) + d(6)

Case 2:  n = 15:  11/2 = a(1) + d(15 - 1) =  a(1) + d(14)

Then our system of linear equations is:

a(1) + 6d = 29/6

a(1) + 14d = 11/2

Let's solve this by elimination by addition and subtraction.  Subtract the first equation from the second.  We get:

                                                             

Substituting 1/12 for d in the first equation, we get:

a(1) + 14(1/12) = 11/2 or 66/12 (using the LCD 12)

Then a(1) = 66/12 - 14/12 = 52/12 = 13/3

The first term is 13/3 and the common difference is d = 1/12

The arithmetic sequence formula for this problem is thus:

a(n) = 13/3 + (1/12)(n - 1)                                                                          8

5 0
3 years ago
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