The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is 
<h3>How to determine the equation of the hyperbola?</h3>
The given parameters are:
- Directrices at x = ±2
- Foci at (5, 0) and (−5, 0)
The foci of a hyperbola are represented as:
Foci = (k ± c, h)
The center is:
Center = (h,k)
And the directrix is:
Directrix, x = h ± a²/c
By comparison, we have:
k ± c = ±5
h = 0
h ± a²/c = ±2
Substitute h = 0 in h ± a²/c = ±2
0 ± a²/c = ±2
This gives
a²/c = 2
Multiply both sides by c
a² = 2c
k ± c = ±5 means that:
k ± c = 0 ± 5
By comparison, we have:
k = 0 and c = 5
Substitute c = 5 in a² = 2c
a² = 2 * 5
a² = 10
Next, we calculate b using:
b² = c² - a²
This gives
b² = 5² - 10
Evaluate
b² = 15
The hyperbola is represented as:
So, we have:
Evaluate
Hence, the equation of the hyperbola is
Read more about hyperbola at:
brainly.com/question/3405939
#SPJ1
Answer:
61.93°
Step-by-step explanation:
sin x=15/17
=0.8824
sin-1 0.8824
=61.93°
Answer:
Quotient: x+7
Remainder: -2
Step-by-step explanation:
Divide the terms (x² ÷ x =x)↓
(x² + 11x + 26) ÷ (x + 4) =x
Subtract x² + 4x (You have to the sign if each term)
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
Divide the terms (7x ÷ x = 7)
x² + 11x + 26) ÷ (x + 4) =x + 7
Multiply the quotient by the dividend (x + 4) × 7 = 7x+28
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
7x + 28
------------------
= -2 Remainder
Bag weight 1.8 kg
Golf ball weight: 45g
1 kg = 1000g
Total bag weight in grams = 1.8 x 1000 = 1800g
total bag weight / golf ball weight = total balls in bag
1800 / 45 = 40
Total balls in bag = 40.
6 is the mode since it appears the most, 3 times
