Cos
θ
=
√
5
3
or it could be cos
θ
=
√
5
−
3
Explanation:
Since sin
θ
is negative, it can be in the third or fourth quadrant
Drawing your right-angled triangle, place your
θ
in one of three corners. Your longest side will be 3 and the side opposite the
θ
will be -2. Finally, using Pythagoras theorem, your last side should be
√
5
Now, if your triangle was in the third quadrant, you would have
cos
θ
=
√
5
−
3
since cosine is negative in the third quadrant
But if your triangle was in the fourth quadrant, you would have
cos
θ
=
√
5
3
since cosine is positive in the fourth quadrant
The 2-point form of the equation of a line can be written as ...
... y = (y2-y1)/(x2-x1)·(x -x1) +y1
For your points, this is ...
... y = (1-5)/(3-6)·(x -6) +5
... y = (4/3)(x -6) +5
It can also be written as
... y -5 = (4/3)(x -6)
Answer:
<u>B. 7(x − 5)(y + 2)</u>
Explanation:
A. 7(2x − 5)(y + 2) = 14xy + 28x − 35y − 70 (Wrong)
<u><em>B. 7(x − 5)(y + 2) = 7xy + 14x − 35y − 70 (Correct)</em></u>
C. 7(x − 2)(y + 5) = 7xy <u>+</u> 35x− 14y − 70 (Wrong)
D. 7(x − 10)(y + 2) = 7xy + 14x − 70y − 140 (Wrong)
