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valkas [14]
3 years ago
5

Due in 10 min Need explination also first helpfull answer will be brainlyest

Mathematics
1 answer:
Doss [256]3 years ago
4 0
My answer is 25 so yeah

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81a raised to the power of 2 minus 25
muminat

81a²-25 would be the answer I'm pretty sure. Hopefully I helped.

8 0
2 years ago
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What is the range of this equation? f(x) = x + 41 – 2
Sergeu [11.5K]
The range is the set of all valid
y
y
values. Use the graph to find the range.
Interval Notation:
(
−
∞
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3 0
2 years ago
Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$
horrorfan [7]

Answer:

A +B+C+D  = 3 is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

A+B+C+D = ? if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under \sqrt (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \   (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, A +B+C+D = 5+6-10+2 = \bold3

5 0
3 years ago
Can anyone help me with this math question
ANTONII [103]

The third is true

ok bye

lm'iranian

11years old

4 0
2 years ago
8
wolverine [178]
Answer:c
explanation: its 90 degrees

good luck!
3 0
2 years ago
Read 2 more answers
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