The expected value of the winnings from the game is $4
<h3>How to determine the expected value?</h3>
The payout probability distribution is given as:
Payout ($) 2 4 6 8 10
Probability 0.5 0.2 0.15 0.1 0.05
The expected value is then calculated as:
This gives
E(x) = 2 * 0.5 + 4 * 0.2 + 6 * 0.15 + 8 * 0.1 + 10 * 0.05
Evaluate the expression
E(x) = 4
Hence, the expected value of the winnings from the game is $4
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Answer:
702.1
Step-by-step explanation:
Use the formula for the diagonal of a cuboid.
√(l^2+b^2+h^2)
√(33^2+56^2+33^2)
√5314
= 702.125345
Hello! I can help you! In general, the larger the size, the larger the cost. We will assume that $8 is the youth size and $12 is the adult size. x is the youth side and y is the adult side. The first part of the equation is 8x + 12y, BUT the key words in the problem are AT MOST, so out sign will be less than or equal to (≤), because the number can't be higher than 216, but it could be right at that number or less, so the equation is 8x + 12y ≤ 216. The answer is A.
29/48 is about 60 percent to the nearest hundredth
Answer:
Play 3
Step-by-step explanation:
Given:
Required [Missing from the question]:
Determine the play with the least change in yard?
To do this, we ignore the sign in front of each yard before we analyze.
So, we have:
Play 1 has a change of 4
Play 2 has 6
Play 3 has 2
Play 4 has 3
<em>From the above analysis, play has the least (which is 2)</em>
