Check the picture below.
so the lateral area of the pyramid is really just the area of four triangles whose base is 10 and height is also 10, now, we're excluding the bottom because that's not lateral area.
![\stackrel{\textit{area of four triangles}}{4\left[\cfrac{1}{2}(\stackrel{b}{10})(\stackrel{h}{10}) \right]}\implies 2(100)\implies \text{\LARGE 200}~ft^2](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20four%20triangles%7D%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7Bb%7D%7B10%7D%29%28%5Cstackrel%7Bh%7D%7B10%7D%29%20%5Cright%5D%7D%5Cimplies%202%28100%29%5Cimplies%20%5Ctext%7B%5CLARGE%20200%7D~ft%5E2)
Answer:
53 cm
Step-by-step explanation:
Using Pythagoras Theorem,
The hypotenuse


= 53 cm
Answer:
The sum of 0.380 and 0.245 would be 0.625
Answer:
Step-by-step explanation:
The area of a rectangle can be found with the formula
, where
is the length of the rectangle and
is the width.
From the given problem statement, we know that
and
, so we can fill in those values in the formula anbd solve for
to get the width:


Divide both sides by
to isolate
by itself:

