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liq [111]
3 years ago
14

A scientist is breeding orange butterflies in the laboratory she notices a white butterfly in the latest generation of animals s

he sequences the genome of this butterfly in notices a mutation in the genes that calls for pigment in the wings. Explain how this mutation would result in a white butterfly.
Chemistry
1 answer:
nevsk [136]3 years ago
7 0

Answer:

See explanation

Explanation:

A gene mutation can be defined as a permanent change in the DNA sequence that composes a gene, resulting in the observation that the sequence differs from what is obtainable in most individuals that make up the  population. Mutations range from a change in a single DNA building block (change in the sequence of base pairs) to changes in a large segment of a chromosome that includes multiple genes.

Mutation in the color of the wings of the housefly can be passed on to the next generation. If this trait enhances survival of the butterflies, the orange winged butterflies will eventual become extinct and become entirely replaced by the white winged butterflies. This implies that gene pool has been completely modified.

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Solve this problems using the equation: C = λ x ν........ A microwave oven emits radiation at a wavelength of 5.00 x 10e-5 m. Wh
stira [4]

Answer:

c = λ x ν

v =c/λ=(3*10e8)/(5.00 x 10e-5)=6000000000000

f = v/λ =6000000000000/5.00 x 10e-5=120000000

Explanation:

4 0
3 years ago
Coal contains _______ energy.<br><br> A) light<br> B) kinetic<br> C) chemical<br> D) mechanical
ololo11 [35]
C chemical since it is after all made of chemicals
3 0
3 years ago
Read 2 more answers
What is the empirical formula?
algol [13]

Question

What is the empirical formula?

Answer:

Hi, There!

  • ,the empirical formula of a chemical is a simple expression of the relative number of each type of atom (called a chemical element)
  • Empirical formula is defined as the formula of a compound which gives the simple whole number ratio of the atoms of various elements present in one molecule of compound.

Hope this Helps!

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5 0
3 years ago
Calculate how many grams of sodium azide (NaN3) are needed to inflate a 25.0 × 25.0 × 20.0 cm bag to a pressure of 1.35 atm at a
Luden [163]

Answer : The mass of NaN_3 at temperature 20^oC 28.47 g.

The mass of NaN_3 at temperature 10^oC 29.51 g.

Solution : Given,

Pressure of gas = 1.35 atm

Temperature of gas = 20^oC=273+20=293K     (0^oC=273K)

Volume of gas = 25\times 25\times 20cm=12500cm^3=12.5L   (1L=1000cm^3)

Molar mass of NaN_3 = 65 g/mole

Part 1 : First we have to calculate the moles of gas at temperature 20^oC. The gas produced in the given reaction is N_2.

Using ideal gas equation,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

Now put all the given values in this formula, we get

(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (293K)

By rearranging the terms, we get the value of 'n'

n=0.7015moles

The moles of N_2 = 0.7015 moles

The given balanced reaction is,

20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)

As, 32 moles of N_2 produced from 20 moles of NaN_3

So, 0.7015 moles of N_2 produced from \frac{20}{32}\times 0.7015=0.438 moles of NaN_3

Now we have to calculate the mass of NaN_3.

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

\text{ Mass of }NaN_3=(0.438moles)\times (65g/mole)=28.47g

Therefore, the mass of NaN_3 needed are 28.47 g.

Part 2 : We have to calculate the moles of gas at temperature 10^oC and same volume & pressure.

Using ideal gas equation,

PV=nRT

Now put all the given values in this formula, we get

(1.35atm)\times (12.5L)=n\times (0.0821Latm/moleK)\times (283K)

By rearranging the terms, we get the value of 'n'

n=0.726moles

The moles of N_2 = 0.726 moles

The given balanced reaction is,

20NaN_3(s)+6SiO_2(s)+4KNO_3(s)\rightarrow 32N_2(g)+5Na_4SiO_4(s)+K_4SiO_4(s)

As, 32 moles of N_2 produced from 20 moles of NaN_3

So, 0.726 moles of N_2 produced from \frac{20}{32}\times 0.726=0.454 moles of NaN_3

Now we have to calculate the mass of NaN_3.

\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3

\text{ Mass of }NaN_3=(0.454moles)\times (65g/mole)=29.51g

Therefore, the mass of NaN_3 needed are 29.51 g.

7 0
3 years ago
A calorimeter contains 35.0 mLmL of water at 15.0 ∘C∘C . When 2.20 gg of XX (a substance with a molar mass of 56.0 g/molg/mol )
Temka [501]

Answer:

ΔH rx = -43.5 kJ / mol

Explanation:

In water, Xdissolves thus:

X(s) + H₂O(l) → X(aq) + H₂O(aq)

It is possible to find the heat in dissolution process using coffee cup calorimeter equation:

Q = -m×C×ΔT

<em>Where Q is heat, m is mass of solution (35.0g -density 1g/mL- + 2.20g = 37.2g), C is specific heat of solution (4.18J/g°C), and ΔT is change in temperature (26.0°C-15.0°C = 11.0°C)</em>

Replacing:

Q = -37.2g×4.18J/g°C×11.0°C

Q = -1710J = -<em>1.71kJ</em>

As enthalpy is the change in heat per mole of reaction, moles of X that reacted were:

2.20g X × (1mol / 56.0g) = <em>0.0393 moles</em>

As heat produced per 0.0393moles was -1.71kJ, heat per mole of X is:

-1.71kJ / 0.0393mol = -<em>43.5 kJ / mol = ΔH rx</em>

6 0
3 years ago
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