Question

How many lbs. of O2 are required to fully convert 1-lb of glucose (C6H12O6) to carbon dioxide and water

Answer 1

Answer:

The correct answer is : 1.07 lbs

Explanation:

solution:

molar mass glucose (C6H12O6) = 180 g/mol

molar mass of oxygen molecule (O2) = 32 g/mol  (as we know molar mass of O = 16 g/mol)

the balanced reaction of conversion of water and oxygen to glucose is:

$C_{6}H_{12}O_{6} + 6O_{2} \rightarrow 6CO_{2} + 6H_{2}O ...(A)$

1 mol of C6H12O6 = 6 mol of O2  (from reaction A)

so, 180 g C6H12O6 = 192 g O2

that is, 0.396 lb of C6H12O6 = 0.423 lb of O2  (  1 g = 0.00220462 lb )

so,

1 lb C6H12O6 =$\frac{1(lb) \times 0.4233 (lb)}{0.3968 (lb)}$ = 1.07 lb O2

therefore,  the correct answer is : 1.07 lbs