A) 390/.3= 1300 , 1300-390= 910, 910/1300= .70 OR 1.00-.3= .7
b) 390/.3= 1300$
c)390/.3= 1300 , 1300-390= 910$
Answer:
5x^2 + 12x -3 =0 ---------> solve by quadratic formula
x^2 -4x = 8 ----------> solve by completing the square
4x^2 -25 = 0 ----------> solve by square root method
x^2-5x+ 6 = 0 -----------> solve by factoring
Step-by-step explanation:
1. 5x^2 + 12x -3 =0
The best way to solve this equation is quadratic formula as all the terms in the equation have coefficients it will be convenient to solve it through quadratic formula.
2. x^2 -4x = 8
The best way to solve this equation is by completing the square as the factors cannot be made directly.
3. 4x^2 -25 = 0
the best way to solve this equation is to solve by square root method as the 25 and 4 are perfect squares.
4. x^2-5x+ 6 = 0
The best way to solve this equation is to solve by factoring as it can clearly be seen that it is convenient to make factors ..
Answer:
X - 7 = - 3
X = - 3 + 7
X = 4
the 7 turns positive because it was moved to the other side of the symbol "=" so we reverse the sign
- becomes +
and
+ becomes -
Using vector concepts, it is found that:
The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.
<h3>How can a vector be represented in component notation?</h3>
Given a magnitude M and angle 
, then a vector V can be represented as follows in component notation:
In this problem, the magnitude and the angle are given, respectively, by:
Hence:
V = [12cos(143º), 12sin(143º)] = (-9.58, 7,22).
Which means a displacement of 9.58 miles to the west(negative x = west) and 7.22 miles to the north(positive y = north).
The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.
More can be learned about vectors at brainly.com/question/24606590
#SPJ1
Answer:
7/11
Step-by-step explanation:
Let X equal the decimal number
Equation 1:
X=0.63¯¯¯¯¯
With 2 digits in the repeating decimal group,
create a second equation by multiplying
both sides by 102 = 100
Equation 2:
100X=63.63¯¯¯¯¯
Subtract equation (1) from equation (2)
100XX99X===63.63...0.63...63
We get
99X=63
Solve for X
X=6399
Find the Greatest Common Factor (GCF) of 63 and 99, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 9,
63÷999÷9=711
Therefore
X=711
In conclusion,
0.63¯¯¯¯¯=711
used
https://www.calculatorsoup.com/calculators/math/decimal-to-fraction-calculator.php
