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Sloan [31]
3 years ago
14

A truck weighs 500 N on Earth. What's the mass of the truck?

Physics
2 answers:
pogonyaev3 years ago
5 0

Answer:

Solution given:

Wight [W]=500N

gravity [g]=10m/s²

mass[m]=?

we have

W=mg

500=m*10

m=500/10

m=50kg

<u>the mass of the truck</u><u> </u><u>i</u><u>s</u><u> </u><u>5</u><u>0</u><u>k</u><u>g</u><u>.</u>

Jobisdone [24]3 years ago
3 0
The answer is 50 kg plz mark as brainliest
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3 years ago
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To test the performance of its tires, a car
velikii [3]

<u>Answer</u>:

The coefficient of  static friction between the tires and the road is 1.987

<u>Explanation</u>:

<u>Given</u>:

Radius of the track, r =  516 m

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Speed,v =  32.8 m/s

<u>To Find:</u>

The coefficient of  static friction between the tires and the road = ?

<u>Solution</u>:

The radial Acceleration is given by,

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a_{R = \frac{(1075.84)}{516}

a_{R = 2.085 m/s^2

Now the total acceleration is

\text{ total acceleration} = \sqrt{\text{(tangential acceleration)}^2 +{\text{(Radial acceleration)}^2

=>= \sqrt{ (a_r)^2+(a_R)^2}

=>\sqrt{ (3.89 )^2+( 2.085)^2}

=>\sqrt{ (15.1321)+(4.347)^2}

=>19.4791 m/s^2

The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of  static friction is

\mu =\frac{f}{W}

From (1) and (2)

\mu =\frac{ma}{mg}

\mu =\frac{a}{g}

Substituting the values, we get

\mu =\frac{19.4791}{9.8}

\mu =1.987

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If a roller coaster train has a potential energy of 1,500 J and a kinetic energy of 500 J as it starts to travel downhill, what
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