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Degger [83]
3 years ago
7

Gravitational potential energy is due to....

Physics
1 answer:
mote1985 [20]3 years ago
5 0

Answer:

A

Explanation:

I only think its A because of the gravity part...sorry im not good at explaining

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If you saw a waxing gibbous moon what phase would you expect one week later?
Leona [35]
Seven days after a waxing gibbous moon, the moon will be waning gibbous, and at some point during that seven days, it will have been Full.
6 0
3 years ago
A backpacker walks for 3 days in the mountains and covers 16 km. How fast was he walking in km/hr?
Fudgin [204]

Answer:

0.22 km/h

Explanation:

72 hours in 3 days

16/72 = 0.222222222

round to 0.22 km/h

For future reference, Distance/Time= Speed

5 0
3 years ago
How are lasers used to determine the distance from earth to the moon?
mezya [45]
A beam of laser is directed at a reflecting surface put on the moon when the beam of laser is reflected a receiver on the each measure the time since the beam was sent till it was received. Laser is simply light so it has constant velocity in vacuum ~ air  (c = 3 x 10^8 m/s)

to find the distance:

t : time measured between launching the beam and receiving it 

d : distance

d = ct 

5 0
3 years ago
Read 2 more answers
Which description does the phrase "mechanical advantage" most closely relate to?
yKpoI14uk [10]
<span>the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of a machine. I would say the answer is D, but i'm not sure. :)</span>
4 0
3 years ago
Find the final temperature of 375 grams of tea (c = 4.184 J/g°C) if its initial temperature is 95°C just before it is placed in
Minchanka [31]

Answer:

the final temperature of the tea is 7.39⁰C.

Explanation:

Given;

mass of the tea, m = 375 g

specific heat capacity of the tea, C = 4.184 JJ/g°C

initial temperature of the tea, t₁ = 95°C

the final temperature of the tea, t₂ = ?

Energy lost by the refrigerator, Q = 137,460 J

The energy lost by the refrigerator is given by the following formula;

-Q = mc(t₂ - t₁)

-137,460 =375 x 4.184(t₂ - 95°C)

-137,460 = 1569(t₂ - 95°C)

t_2-95 = \frac{-137,460}{1569} \\\\t_2-95 = -87.61\\\\t_2 = -87.61 + 95\\\\t_2 = 7.39 \ ^0 C

Therefore, the final temperature of the tea is 7.39⁰C.

4 0
3 years ago
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