Initial velocity, u = 4 m/s
acceleration due to gusts of wind = 3 m/s^2
time, t = 1 min = 60 s
Let distance travelled = S
From equation of motion,
![S = ut + \frac{1}{2} a {t}^{2} \\ \\ S = 4 \times 60 + \frac{1}{2} \times 3 \times {60}^{2} \\ \\ S = 240 + 5400 \\ \\ S = 5640 \: m](https://tex.z-dn.net/?f=S%20%3D%20ut%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20a%20%7Bt%7D%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20S%20%3D%204%20%5Ctimes%2060%20%2B%20%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%203%20%5Ctimes%20%20%7B60%7D%5E%7B2%7D%20%20%5C%5C%20%20%5C%5C%20S%20%3D%20240%20%2B%205400%20%5C%5C%20%20%5C%5C%20S%20%3D%205640%20%5C%3A%20m)
Thus, the boat would have traveled 5640m after gusts picked up.
Answer:
TO answer this question i need wave speed
Explanation:
KE = 1/2 x 80 x 60^2
KE = 144000
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