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Elanso [62]
3 years ago
11

A painter needs to cover a triangular region 60 meters by 77 meters by 89 meters. A can of paint covers 80 square meters of area

. Find the area of the triangular region, rounded to the nearest square meter.
Mathematics
1 answer:
bixtya [17]3 years ago
4 0
Perimeter = 60 + 68 +71 = 199
SEMI-Perimeter = 199/2 = 99.5
Area = sq root (99.5 * (99.5-60) * (99.5-68) * (99.5-71)
Area = sq root (99.5 * 39.5 * 31.5 * 28.5)
Area = sq root ( 3,528,381.94 )
Area = 1,878.4 square meters
1,878.4 / 70 sq mtr per can means you will need
26.83 cans OR 27 cans
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One term of a geometric sequence is a6 = 224. The common ratio is r = 2. What is the rule fo the nth term?
Dovator [93]

Answer: Equation

Such sequences can be expressed in terms of the nth term of the sequence. In this case, the nth term = 2n. To find the 1st term, put n = 1 into the formula, to find the 4th term, replace the n's by 4's: 4th term = 2 × 4 = 8.

Step-by-step explanation:

7 0
4 years ago
Plz help I just need numbers
insens350 [35]

Answer:

(0, 0)

Vertex: (1, -5)

(2, 0)

3 0
4 years ago
:= Question Help
artcher [175]

Answer: OC

Step-by-step explanation: exact answer is 64.6

7 0
3 years ago
1. How many times greater is the value of the 6 in 9,638 than the value of the 6 in 3,968?
Oksana_A [137]

Answer:

100 times

Step-by-step explanation:

doesn't matter if the number is in the same place value so, the answer is 100 times.

6 0
3 years ago
In a sequence of ten terms, each term (starting with the third term) is equal to the sum of the two previous terms. The seventh
poizon [28]

Answer:

\boxed{a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8+a_9+a_{10}=66}

Step-by-step explanation:

We know that in a sequence of ten terms, each term (starting with the third term) is equal to the sum of the two previous terms. The seventh term is equal to 6. Therefore, we have

a_1+a_2=x\\a_3=x\\a_4=2x\\a_5=3x\\a_6=5x\\a_7=8x\\

We know that:

a_7=6\\\implies 8x=6\\x=\frac{3}{4}

We get:

a_1+a_2=x=\frac{3}{4}\\\\a_3=x=\frac{3}{4}\\\\a_4=2x=\frac{3}{2}\\\\a_5=3x=\frac{9}{4}\\\\a_6=5x=\frac{15}{4}\\\\a_7=8x=6\\\\a_8=13x=\frac{39}{4}\\\\a_9=21x=\frac{63}{4}\\\\a_{10}=34x=\frac{102}{4}\\

Therefore, we calculate

\boxed{a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8+a_9+a_{10}=66}

4 0
3 years ago
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