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Harman [31]
3 years ago
11

What is the volume of a hexagonal pyramid with a side length of 4 inches and a height of 12 inches (answer in the radical form p

lease)? Thanks in advance
Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

Step-by-step explanation:

formula for the volume of a hexagonal pyramid is (\sqrt{3}/2)*a^{2}*h

where is is the side length, for this pyramid it's 4

and h is the height, for this pyramid it's 12

(\sqrt{3}/2)*4^{2}*12 = 96*\sqrt{3}

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See Below.

Step-by-step explanation:

In the given figure, AP = BP = PC.

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Since AP = BP and BP = PC, we can create two isosceles triangles: ΔAPB and ΔCPB.

By the definition of isosceles triangles, in ΔAPB, ∠PAB and ∠PBA are equivalent. Let the measure of each of them be <em>x°</em>.

Likewise, in ΔCPB, ∠PCB and ∠PBC are equivalent.

And since AP = BP = PC, each of the angles∠PCB and ∠PBC will also be equivalent to <em>x°.</em>

<em />

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