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Nonamiya [84]
3 years ago
7

Please help if you have the correct answer to the post test manufacturing and safety answer.

Computers and Technology
1 answer:
Fed [463]3 years ago
8 0
I believe it is corn. ethanol can be produced from corn biomass, and is commonly used to make gasoline. i’m not sure if this answers your question, or counts as a type of energy but i tried.
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This is not what I asked for​
jolli1 [7]
?? What does that mean? What is the question
3 0
3 years ago
function outputValue = AdjustOutput(outputValue, amplitudeResponse, phaseResponse) % Write an if-statement that subtracts 5 from
MatroZZZ [7]

Answer:

function outputValue = AdjustOutput(outputValue, amplitudeResponse, phaseResponse)

if amplitudeResponse > 10

outputValue = outputValue - 5;

else

outputValue = outputValue;

end

if phaseResponse < 275

outputValue = outputValue + 3;

else

outputValue = outputValue

end

end

AdjustOutput(20, 15, 149)

6 0
3 years ago
The process of determining that a user has permission to perform a particular action on a computer is called
Doss [256]
I believe that would be authorization.
5 0
3 years ago
Matching parentheses. An math expression may have a number of parentheses like (, ), [, ], { and }. Each openning parenthesis (,
Solnce55 [7]
C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}


Sample Input/Output is attached

3 0
2 years ago
Imagine that you are investigating a crime of fraud, where the suspect is creating false documents. Where might you look for evi
kolbaska11 [484]
You would look in the documents folder on the persons computer. You could also look for photo file types if the perp was using photoshop to make changes to documents and then printing them. 
4 0
3 years ago
Read 2 more answers
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