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3 years ago

9

WILL MARK BRAINLIEST! PLEASE HELP!

1 answer:

mash [69]3 years ago

5 0

I think 32..............

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Just a little help for Brainliest

Viefleur [7K]

Answer:

what are you calculating here

Step-by-step explanation:

7 0

3 years ago

Please help me with the problem

mixas84 [53]

Let's see what we're working on here

$\frac{1}{2} - 2(m) =?$
? = 0
$Simplify this →$ $\frac{1}{2}$

$\frac{1}2y} - 2(m) = ?$

$\frac{2(m)(2)}{2}$

$\frac{1 - 4(m)}{2} = ?$

$\frac{1 - 4(m)}{2} = 2$

$-4(m) + 1 = 0$
Subtract ( - )the number 1 from each of your sides on this part

4(m) = 1
Multiply( ×) the number -1 to your sides for this part of the equation

Therefore, the value of m is $\frac{1}{4}$
$m = \frac{1}{4}$

3 0

4 years ago

Read 2 more answers

There are 32 students in the cafeteria, 12 girls and 20 boys. What is the ratio

tiny-mole [99]

Answer:

A

Step-by-step explanation:

12/4=3

20/4=5

5 0

3 years ago

Read 2 more answers

Which expression represents the area of the shaded region?

irina1246 [14]

Given:

A circle of radius r inscribed in a square.

To find:

The expression for the area of the shaded region.

Solution:

Area of a circle is:

$A_1=\pi r^2$

Where, r is the radius of the circle.

Area of a square is:

$Area=a^2$

Where, a is the side of the square.

A circle of radius r inscribed in a square. So, diameter of the circle is equal to the side of the square.

$a=2a$

So, the area of the square is:

$A_2=(2r)^2$

$A_2=4r^2$

Now, the area of the shaded region is the difference between the area of the square and the area of the circle.

$A=A_2-A_1$

$A=4r^2-\pi r^2$

$A=4r^2-\pi r^2$

$A=r^2(4-\pi )$

Therefore, the correct option is (a).

5 0

3 years ago

Scrat [10]

Answer: Ix - 950°C I ≤ 250°.

Step-by-step explanation:

Ok, the limits are:

700°C to 1200°C.

The first step is to find the mean these numbers:

M = (700°C + 1200°C)/2 = 950°C

Now let's find the distance between the mean and the limits (which is equal to half the difference between our numbers)

D = (1200°C - 700°C)/2 = 250°C.

Now we can write our relation as:

Ix - MI ≤ D

Ix - 950°C I ≤ 250°.

if x = 1200°C.

I1200°C - 950°CI = 250°C ≤ 250°C ---- true.

if x = 700°C

I700°C - 950°CI = I-250°CI = 250°C ≤ 250°C ---- true

7 0

3 years ago