let me edit your question as:
Which two equations are true?
<u>Eq1:</u>
(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)
<u>Eq2:</u>
6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)
<u>Eq3:</u>
2.7×103(7.5×106)−(2.5×106)=5×100
Answer:
No one is true
Step-by-step explanation:
let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.
Using PEMDAS rule we are simplifying the equations as;
<u>Eq1:</u>

<u>Eq2:</u>
<u></u>
<u></u>
<u>Eq3:</u>

<u>we observed that none of the equation has two same values on both sides thus none of the three equations is true.</u>
<u>Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true</u>
A cube has six sides so you divide 3750 by 6 to find the area of a single face. This would be 625. Area is length times width and since it is a cube you know that both are the same. This gives you an answer of 25.
The first one is 23/30 and the second one is 2 19/24
Step-by-step explanation:
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Answer:

Step-by-step explanation:
Ask yourself, when will Xavier and Yolanda meet??
Firstly, since it is given that Xavier doesn't wait at all, in order for them to meet, Yolanda must arrive before Xavier. This in mathematical terms can be expressed as

Secondly, Yolanda will wait for only 45 minutes, So Xavier must arrive before that, i.e

Combining both conditions, we obtain

If
and
be the density functions for Xavier and Yolanda respectively, the probability of meeting is given by,
.