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s2008m [1.1K]
3 years ago
10

A car travels 15 miles in 30 minutes . calculate the average speed

Physics
1 answer:
Greeley [361]3 years ago
5 0

Answer:

15/30 = .5 miles/m

Explanation:

v = d/t

velocity = 15 / 30

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In deserts the temperatures can reach extreme values in deep of summer and winter. A steel bridge is being constructed and it is
ryzh [129]

Answer:

The length of the bridge during the hottest part of summer is L_s  = 1235.925 m

Explanation:

From the question we are told that

    The length of the steel bridge is L = 1234.567m

     The temperature for this length is T_1 = 233.15K

     The temperature at summer T_2  = + 140.0F = \frac{140 - 32}{180} *100  + 273= 333 K

     The coefficient of linear expansion is \alpha  = 11.0123*10^{-6} K^{-1}

Generally the change in length of the steel bridge is mathematically represented as

             \Delta L = \alpha L \Delta T

Substituting value

             \Delta L = 11.0123*10^{-6}  * 1234.567 (333-233.15)

              \Delta L = 1.3575 \ m

The length of the bridge in summer is mathematically evaluated as

         L_s  = L + \Delta L

Substituting values

         L_s  = 1234.567 + 1.3575

        L_s  = 1235.925 m

3 0
3 years ago
A man can lift a mass of 200kg onThe surface of the earth. what is the amount of mass he can lift on the surface of the moon?
Arlecino [84]

Answer:

1,211.1 kg.

Explanation:

the force of gravity is less on the moon than on earth, so if the man can lift 200kg on earth, he could lift a greater amount on the moon because there is less resistance from gravity.

To know the amount of mass he can lift on the moon, we first need to know the amount of weight that is equivalent to those 200kg here on earth. This because the weight of the object is equal to the force that must be applied to lift it, and that force is applied by the man and it will be the same here and on the moon.

We calculate weight using the formula:

w=mg

where w is the weight of the object (the force with which the earth attracts the object) m is the mass and g the acceleration of gravity.

so

w=200g

for earth the acceleration due to gravity is:  g=9.81m/s^2

thus:

w=(200kg)(9.81m/s^2)\\w=1962N

now we use this value to calculate the mass he can lift on the moon, since for the moon g=1.62m/s^2.

we use the same equation, w =mg substituting w = 1962N and g=1.62m/s^2:

w=mg\\\\1962N=m(1.62m/s^2)\\\\m=\frac{1962N}{1.62m/s^2}\\\\ m=1,211.1kg

he can lift 1,211.1 kg.

You can also find the result using the approximate value of the acceleration of gravity on the moon as g/6, where g is the acceleration on earth.

8 0
4 years ago
2. A gas with a constant pressure of 270 kPa does 36,000 J of work as it expands.
liberstina [14]
C sorry if wrong ,,,
5 0
3 years ago
For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg
jeyben [28]

Answer:

<h2>Magnetic field strength in that region is 1.2 T</h2>

Explanation:

As we know by the formula of radius of charge moving in external field is given as

R = \frac{mv}{qB}

so we will have

R = 25 cm

m = 1.6 \times 10^{-27} kg

q = 1.6 \times 10^{-19} C

v = 0.10 \times 3 \times 10^8 m/s

now we have

0.25 = \frac{(1.6 \times 10^{-27})(3\times 10^7)}{(1.6 \times 10^{-19})B}

now we have

B = 1.2 T

8 0
3 years ago
Show that linear S.H.M is projection of a U.C.M along any of its diameter
BigorU [14]

It shows that acceleration of particle M is directly proportional to its displacement and its direction is opposite to that of displament. Thus particle M performs simple harmonic motion but M is projection of particle performing U.C.M. hence S.H.M. is projection of U.C.M. along a diameter, of circle.

4 0
3 years ago
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