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Ilya [14]
3 years ago
7

A cardinal (Richmondena cardinalis) of mass 3.70×10−2 kg and a baseball of mass 0.144 kg have the same kinetic energy. What is t

he ratio of the cardinal's magnitude pc of momentum to the magnitude pb of the baseball's momentum?

Physics
2 answers:
Radda [10]3 years ago
3 0

Answer:

\frac{p_{c}}{p_{b}}\approx 0.507

Explanation:

Since the cardinal and ball have the same kinetic energy, it is possible to determine the ratio between speeds. (c for cardinal, b for baseball)

K_{c} = K_{b}

\frac{1}{2}\cdot m_{c}\cdot v_{c}^{2}= \frac{1}{2}\cdot m_{b}\cdot v_{b}^{2}

\frac{v_{c}}{v_{b}}=\sqrt{\frac{m_{b}}{m_{c}} }

The ratio is obtained by multiplying each side by \frac{m_{c}}{m_{b}}:

\frac{p_{c}}{p_{b}}=\frac{m_{c}}{m_{b}}\cdot \sqrt{\frac{m_{b}}{m_{c}} }

\frac{p_{c}}{p_{b}}= \sqrt{\frac{m_{c}}{m_{b}} }

The value of this ratio is:

\frac{p_{c}}{p_{b}}\approx 0.507

KIM [24]3 years ago
3 0

Explanation:

Below is an attachment containing the solution.

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From the options provided the best description of scissor is that scissors helps to scrap things down. This is the main purpose of scissors, to cut things, and by doing so you are breaking up a larger object into smaller and more manageable scraps. We can get rid of the other options because scissors are made of metal and therefore not soft and are not necessarily dull since they need to be sharp to fulfill their purpose. Although a pair of scissors has two holes it is not necessarily the best description of it.

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A ball filled with an unknown material starts from rest at the top of a 2 m high incline that makes a 28o with respect to the ho
Lady_Fox [76]

Answer:

<u>Searching in google I found the total mass and the radius of the ball (m = 1.5 kg and r = 10 cm) which are needed to solve the problem!</u>  

The ball rotates 6.78 revolutions.

     

Explanation:

<u>Searching in google I found the total mass and the radius of the ball (m = 1.5 kg and r = 10 cm) which are needed to solve the problem!</u>        

At the bottom the ball has the following angular speed:

\omega_{f} = \frac{v_{f}}{r} = \frac{4.9 m/s}{0.10 m} = 49 rad/s

Now, we need to find the distance traveled by the ball (L) by using θ=28° and h(height) = 2 m:

sin(\theta) = \frac{h}{L} \rightarrow L = \frac{h}{sin(\theta)} = \frac{2 m}{sin(28)} = 4.26 m

To find the revolutions we need the time, which can be found using the following equation:                

v_{f} = v_{0} + at  

t = \frac{v_{f} - v_{0}}{a} (1)

So first, we need to find the acceleration:

v_{f}^{2} = v_{0}^{2} + 2aL \rightarrow a = \frac{v_{f}^{2} - v_{0}^{2}}{2L}    (2)  

By entering equation (2) into (1) we have:

t = \frac{v_{f} - v_{0}}{\frac{v_{f}^{2} - v_{0}^{2}}{2L}}

Since it starts from rest (v₀ = 0):  

t = \frac{2L}{v_{f}} = \frac{2*4.26 m}{4.9 m/s} = 1.74 s

Finally, we can find the revolutions:  

\theta_{f} = \frac{1}{2} \omega_{f}*t = \frac{1}{2}*49 rad/s*1.74 s = 42.63 rad*\frac{1 rev}{2\pi rad} = 6.78 rev

Therefore, the ball rotates 6.78 revolutions.

I hope it helps you!                                                                                                                                                                                          

3 0
2 years ago
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