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aliina [53]
3 years ago
8

Loggers cut down 2 identical trees. One tree was cut down with a hand saw and one was cut down with an electric saw. Which activ

ity involved more work? Which one involved more power?
Physics
1 answer:
alex41 [277]3 years ago
8 0
The hand saw involved more work and the electric saw involved more power.
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A car goes from 80 km/h to 20 km/h in 0.5 h. What is the acceleration in km/h2?
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The answer is attached below.
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4 years ago
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If for a given pair of media CR
nika2105 [10]

CR​ < CY​ < CB​

<h3>Which factors affect the critical angle for a given pair of media?</h3>

The factors which affect the critical angle are

(a) The colour (or wavelength) of light

(b) The temperature

(i) Effect of colour of light: The critical angle for a pair of media is less for the violet light and more for the red light. Thus the critical angle increases with the increase in wavelength of light.

(ii) Effect of temperature: The critical angle increases with increase in temperature because on increasing temperature of medium, its refractive index decreases.

According to the question,

μ 1​ sinCR​ =1

μ 2​ sinCY =1

μ 3​ sinCB​ =1

μ 1​ > μ 2​  and μ 2​ > μ 3

⟹μ 1​ > μ 2​ > μ 3

CR​ < CY​ < CB​

Thus,

The critical angle increases with the increase in wavelength of light.

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7 0
2 years ago
I need 2 examples for each one of Newton's 3 Laws
marusya05 [52]

Answer:

1. An object in motion will stay in motion: A car, and its breaks.

2. Force = mass x acceleration: Kicking a ball.

3. Equal or Opposite reaction: Tugging on your dogs leash as hes trying to run off.

Explanation:

5 0
3 years ago
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Explain the difference between contact and non-contact forces. Give an example of each
Amiraneli [1.4K]

pushing on something that pushes back = action and reaction.

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3 years ago
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The drawing shows a hydraulic chamber with a spring (spring constant = 1600 N/m) attached to the input piston and a rock of mass
Triss [41]

Answer:

\Delta x=245\ mm

Explanation:

Given:

  • spring constant of the spring attached to the input piston, k=1600\ N.m^{-1}
  • mass subjected to the output plunger, m=40\ kg

<u>Now, the force due to the mass:</u>

F=m.g

F=40\times 9.8

F=392\ N

<u>Compression in Spring:</u>

\Delta x=\frac{F}{k}

\Delta x=\frac{392}{1600}

\Delta x=0.245\ m

or

\Delta x=245\ mm

8 0
4 years ago
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