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2 years ago

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If Mai ran 6.3 kilometers in 45 minutes how far did she run HELP

1 answer:

8090 [49]2 years ago

3 0

How far did she run for how long?? because she ran 0.14/km so 0.14 multiplied by however many minutes is how far she ran in a certain amount of minutes.

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Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)

jeyben [28]

Answer:

The vertex: $(\frac{3}{4},-\frac{41}{4} )$

The vertical intercept is: $y=-8$

The coordinates of the two intercepts of the parabola are $(\frac{3+\sqrt{41} }{4} , 0)$ and $(\frac{3-\sqrt{41} }{4} , 0)$

Step-by-step explanation:

To find the vertex of the parabola $4x^2-6x-8$ you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em> $a=4, b=-6, \:and \:c=-8$ </em>

2. You can apply this formula to find x-coordinate of the vertex

$x=-\frac{b}{2a}$ , so

$x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}$

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex ( $f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c$ )

$f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}$

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

$f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8$

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

$\mathrm{Add\:}8\mathrm{\:to\:both\:sides}$

$x^2-6x-8+8=0+8$

$\mathrm{Simplify}$

$4x^2-6x=8$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2$

$\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{41}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

$x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}$

4 0

2 years ago

Just help, my brain shutdown and its currently 9:51, so help me asap. <3

Sergeu [11.5K]

Answer:

B hope this helps!

Step-by-step explanation:

Trust <3

4 0

2 years ago

Read 2 more answers

PLEASE HELP WITH THIS ONE QUESTION

Nana76 [90]

Answer:

I'm not sure about the factors, but it's reflected over the x axis if they helps narrow it down

3 0

2 years ago

The ordered pair (3,9) is located in what quadrant? Quadrant I Quadrant II Quadrant III Quadrant IV 2 points QUESTION 2 If you m

galben [10]

For the first question the answer would be the first quadrant
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8 0

2 years ago

Read 2 more answers

What is the equation of a line that has a slope of 0 and goes through the point (4, 10)?

kompoz [17]

Answer:

y =10

Step-by-step explanation:

The equation of a line in point slope form is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is the point on the line

Given

m = 0 and (x0, y0) = (4, 10)

On substituting;

y - 10 = 0(x-4)

y - 10 = 0

y = 0+10

y = 10

Hence the required equation of the line is y =10

4 0

2 years ago