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inysia [295]
3 years ago
9

Las fracciones que tienen denominador 10, 100, 1000, etc las llamamos fracciones decimales y a su vez las podemos escribir como

nummeros decimales 1) encierro las fracciones decimales con color 21/10; 43/8 ;31/12 ;439/100 ;34/10 ;84/7 , 35/1000 ;28/15 ;851/1000
Mathematics
1 answer:
Sindrei [870]3 years ago
8 0

Answer:

las fracciones decimales son:

21/10 = 2,1

439/100 = 4,39

34/10 = 3,4

35/1000 = 0,035

851 / 1000 = 0,851

Step-by-step explanation:

Toda fraccion cuyo denominador (el numero de abajo) es multiplo de 10 es considerada una fraccion decimal. No importa si el numerador es mayor al denominador. Justamente el sistema decimal fue concebido para facilitar la multiplicacion y division de los numeros por algun multiplo de 10.

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How to turn a fraction into a division problem?
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A science teacher has a supply of 5% hydrochloric acid and a supply of 65% hydrochloric acid(HC1). How much of each solution sho
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Assume that the amount needed from the 5% solution is x and that the amount needed from the 65% solution is y.

We are given that, the final solution should be 42 ml, this means that:
x + y = 42 ...........> equation I
This can also be written as:
x = 42-y .......> equation II

We are also given that the final concentration should be 45%, this means that:
5% x + 65% y = 45% (x+y)
0.05x + 0.65y = 0.45(x+y)


We have x+y = 42 from equation I, therefore:
0.05x + 0.65y = 0.45(42)
0.05x + 0.65y = 18.9 .........> equation III

Substitute with equation II in equation III as follows:
0.05x + 0.65y = 18.9
0.05(42-y) + 0.65y = 18.9
2.1 - 0.05y + 0.65y = 18.9
0.6y = 18.9 - 2.1
0.6y = 16.8
y = 28 ml

Substitute with y in equation II to get x as follows:
x = 42-y
x = 42 - 28
x = 14 ml

Based on the above calculations:
amount of 5% solution = x = 14 ml
amount of 65% solution = y = 28 ml
The correct choice is:
The teacher will need 14 mL of the 5% solution and 28 mL of the 65% solution.
6 0
3 years ago
How do you solve this please help
coldgirl [10]

Answer:

thanks

Step-by-step explanation:

I have been patient trying to get a job

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3 years ago
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