Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
Answer:
B
Step-by-step explanation:
Hope this helps you out! :)
Answer:
1. 37, 2. 1 2/5
Step-by-step explanation:
For Question 1:
Step 1: Replace the x values
x= 3, y=5
Now you get...
9x + 2y ---> (9 x 3) + (2 x 5)
(Remember, if an x value is beside a number, and it is replaced, that replaced number is to be multiplied with the number the previous x value was.)
Parentheses first, Multiplication second, Addition third (look at PEMDAS below :) )
Step 2: Multiply and Add
(9 x 3) + (2 x 5)
27 + 10
37
For Question 2:
Step 1: Replace the x and y values
m = 1, p = 5
Now your equation should look like this:
m + p ÷ 5 ---> 1 + 2 ÷ 5
Now, which one to do first? Use the PEMDAS strategy
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
You have to do it from top to bottom
Division comes first, which means, you have to divide first, then add:
2 ÷ 5 = 2/5
2/5 + 1 = 1 2/5
Hope this helps :)
-jp524
Answer:
Between 67 and 103 beats per minute
Step-by-step explanation:
The minimum would be 80. That means that the minimum sum would have to be 320 among the four numbers.
85+81+87=253
320-253=67 so 67 will be the minimum
now, we should see the maximum. It will be 89 so the sum of the four numbers cannot be anymore than 89*4 which is 356
So, 356-253=103
