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Ilya [14]
2 years ago
14

Someone plz help me

Mathematics
2 answers:
FrozenT [24]2 years ago
8 0

Answer:A

Step-by-step explanation:

konstantin123 [22]2 years ago
3 0

Answer:

temperature

Step-by-step explanation:

it dropped by 15 so it subtracted 15. - 15

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A rock was thrown from the top of a cliff such that its distance above sea level was given by s(t)= at² + bt + c, where t is the
frutty [35]

Answer:

<h2>a) a = -3, b = 18, c = 48; </h2><h2>s(t) = -3t²+18t+48</h2><h2>b) 48m</h2><h2>c) 8secs</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

'A rock was thrown from the top of a cliff such that its distance above sea level was given by s(t)=at²+bt+c, where t is the time in seconds after the rock was released. After 1 second the rock was 63 m above sea level, after 2 seconds 72 m, and after 7 seconds 27 m. a. Find a, b and c and hence an expression for s(t). b. Find the height of the cliff. c. Find the time taken for the rock to reach sea level.'

Given the equation of the distance modelled as s(t)=at²+bt+c

If after 1 second the rock was 63 m, then 63 = a+b+c

If after 2 seconds, the distance was 72 m then 72 = 4a+2b+c

Also if after 7 seconds, the distance is 27 m, then 27 = 49a+7b+c

i) Solving the 3 equations simultaneously to get a, b and c we have;

a+b+c = 63 ... 1

4a+2b+c = 72 ...2

49a+7b+c = 27 ...3

Subtracting 2 from 1 and 3 from 2 we will generate 2 new equations as shown;

eqn 2- eqn1: 3a + b = 9...4

eqn 3- eqn 2: 45a + 5b = -45

eqn 3- eqn 2: 9a+b = -9 ... 5

solving 4 and 5 simultaneously

3a + b = 9 ...4

9a+b = -9 ... 5  

Taking the difference of 4 and 5 we have

6a - -9-9

6a = -18

a = -3

substituting a = -3 into equation 4 to get b we have;

3(-3)+b = 9

-9 + b = 9

b = 9+9

b = 18

substituting a = -3 and b = 18 into equation 1 to get c we have;

-3+18+c = 63

15+c = 63

c = 48

a = -3, b= 18 and c = 48

The distance function will be s(t) = -3t²+18t+48

ii) If the height of the cliff is modelled by the equation  s(t)=at²+bt+c

The height of the cliff is at when t = 0

s(0) = -3(0)²+18(0)+48

s(0) = 48m

The height of the cliff is 48m

iii) At the sea level, the height of the rock will be 0m, substituting this into the modeled equation for the height to get the time we have;

s(t)=at²+bt+c

0 = -3t²+18t+48

3t²-18t-48 = 0

t² - 6t - 16 =0

t² - 8t+2t - 16 = 0

t(t-8)+2(t-8) = 0

(t+2)(t-8) = 0

t = -2 or 8

Taking the positive value of the time, t = 8secs

Time taken for the rock to reach sea level is 8secs

7 0
3 years ago
Hours<br>7 2/3<br>1 2/5<br>4 3/4<br>8 4/5​
VLD [36.1K]
1. 7 hours and 40 min
2. 1 hour and 24 min
3. 4 hours and 45 min
4. 8 hours and 48 min
3 0
3 years ago
PLEASE ANSWER ASAP!!! ILL MARK YOU BRAINLIEST!!<br><br> What is the value of m?
Marizza181 [45]
It's three the m means nothing in this case
6 0
3 years ago
Graph the quadratic function f(x)= -2x^2-3x+2
schepotkina [342]

Answer:

it would be the graph with the maximum (opening down) in the first photo with the top on the left side of the y axis

4 0
3 years ago
X + y = 6
pantera1 [17]
X+y=6
2x+y=4
solve the both
x+y=6
- (2x+y=4)
-x = 2
x=-2
substitute the value of x in x+y=6
-2+y=6
y=6+2
y=8
therefore the answer is (-2,8)

4 0
3 years ago
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