All categories

3 years ago

PLEASE HELP I'LL GIVE BRAINLIEST

Mathematics

2 answers:

Tasya [4]3 years ago

5 0

Answer:a

Step-by-step explanation:

Hunter-Best [27]3 years ago

4 0

You don’t pay attention in class do you it’s A

You might be interested in

Answer this volume based Question. I will make uh brainliest + 50 points

Harlamova29_29 [7]

Answer:

$\huge{\purple {r= 2\times\sqrt[3]3}}$

$\huge 2\times \sqrt [3]3 = 2.88$

Step-by-step explanation:

For solid iron sphere:
radius (r) = 2 cm (Given)

Formula for $V_{sphere}$ is given as:

$V_{sphere} =\frac{4}{3}\pi r^3$

$\implies V_{sphere} =\frac{4}{3}\pi (2)^3$

$\implies V_{sphere} =\frac{32}{3}\pi \:cm^3$

For cone:
r : h = 3 : 4 (Given)
Let r = 3x & h = 4x

Formula for $V_{cone}$ is given as:

$V_{cone} =\frac{1}{3}\pi r^2h$

$\implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)$

$\implies V_{cone} =\frac{1}{3}\pi (36x^3)$

$\implies V_{cone} =12\pi x^3\: cm^3$

It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
$\implies V_{cone} = V_{sphere}$

$\implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}$

$\implies 12x^3= \frac{32}{3}$

$\implies x^3= \frac{32}{36}$

$\implies x^3= \frac{8}{9}$

$\implies x= \sqrt[3]{\frac{8}{3^2}}$

$\implies x={\frac{2}{ \sqrt[3]{3^2}}}$

$\because r = 3x$

$\implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}$

$\implies r=3\times 2(3)^{-\frac{2}{3}}$

$\implies r= 2\times (3)^{1-\frac{2}{3}}$

$\implies r= 2\times (3)^{\frac{1}{3}}$

$\implies \huge{\purple {r= 2\times\sqrt[3]3}}$
Assuming log on both sides, we find:

$log r = log (2\times \sqrt [3]3)$

$log r = log (2\times 3^{\frac{1}{3}})$

$log r = log 2+ log 3^{\frac{1}{3}}$

$log r = log 2+ \frac{1}{3}log 3$

$log r = 0.4600704139$

Taking antilog on both sides, we find:

$antilog(log r )= antilog(0.4600704139)$

$\implies r = 2.8844991406$

$\implies \huge \red{r = 2.88\: cm}$

$\implies 2\times \sqrt [3]3 = 2.88$

8 0

2 years ago

equation of a line in slo[e-intercept form given the slope = 6 and it passes through the point (1, 8)

Luba_88 [7]

Answer:

math way

Step-by-step explanation:

5 0

3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days,

Gnom [1K]

Answer:

a) The mean number of radioactive atoms that decay per day is 81.485.

b) 0% probability that on a given day, 50 radioactive atoms decayed.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval.

a. Find the mean number of radioactive atoms that decayed in a day.

29,742 atoms decayed during 365 days, which means that:

$\lambda = \frac{29742}{365} = 81.485$

The mean number of radioactive atoms that decay per day is 81.485.

b. Find the probability that on a given day, 50 radioactive atoms decayed.

This is P(X = 50). So

$P(X = 50) = \frac{e^{-81.485}*(81.485)^{50}}{(50)!} = 0$

0% probability that on a given day, 50 radioactive atoms decayed.

5 0

3 years ago

Please help me with these

Alex Ar [27]

When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
$\lim_{x \to 0} (\frac{sinx}{x}) = 1$
$\lim_{x \to 0} (\frac{tanx}{x}) = 1$
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) $\lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}$

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
$\frac{\sqrt{0} - 5}{0 - 25}$
$= \frac{-5}{-25}$
$= \frac{1}{5}$

<em>Method 2: Rearranging the function
</em>
We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

$\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}$
$= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}$
$= \frac{1}{5}$

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.

8 0

3 years ago

Simplify the given expression. (16x^2 + 15xy – 19y^2) – (3x^2 – 3xy)

ruslelena [56]

Answer:

-19 y^2 + 18 x y + 13 x^2

Step-by-step explanation:

Simplify the following:

16 x^2 + 15 x y - 19 y^2 - (3 x^2 - 3 x y)

Factor 3 x out of 3 x^2 - 3 x y:

16 x^2 + 15 x y - 19 y^2 - 3 x (x - y)

-3 x (x - y) = 3 x y - 3 x^2:

16 x^2 + 15 x y - 19 y^2 + 3 x y - 3 x^2

Grouping like terms, 16 x^2 + 15 x y - 19 y^2 - 3 x^2 + 3 x y = -19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2):

-19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2)

x y 15 + x y 3 = 18 x y:

-19 y^2 + 18 x y + (16 x^2 - 3 x^2)

16 x^2 - 3 x^2 = 13 x^2:

Answer: -19 y^2 + 18 x y + 13 x^2

4 0

3 years ago

Read 2 more answers