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3 years ago

1. Express the following as a product of its any two factors (in four different ways).

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

7 0

Answer:

It’s c

Step-by-step explanation:

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Simplify the following expression. (19x + 4y) + (49x + 32y)

Valentin [98]

Answer:

68x + 36y

General Formulas and Concepts:

Order of Operations: BPEMDAS
Combining like terms

Step-by-step explanation:

Step 1: Define expression

(19x + 4y) + (49x + 32y)

Step 2: Simplify expression

Combine like terms (x): 68x + 4y + 32y
Combine like terms (y): 68x + 36y

4 0

3 years ago

PLEASE HELP ASAP!!!

xeze [42]

Answer:

JM = 10

Step-by-step explanation:

Because MN║JL,

$\frac{MK}{JM} = \frac{KN}{NL}$

$\frac{5}{2x + 4} = \frac{6}{12}$ = $\frac{1}{2}$

2(5) = 1(2x + 4)

10 = 2x + 4

2x = 6

x = 3

JM = 2x + 4 = 2(3) + 4 = 6 + 4 = 10

6 0

3 years ago

F(x) = 4x2 – 7x + 7 Find f (7)

Colt1911 [192]

Answer:

4×2÷8

so 8+7=15

=7x=15

so,x=15/7

5 0

3 years ago

Read 2 more answers

The points (0,2) and (1,5) are on a line which of these points is on the same line

katrin [286]

Answer:

y = 3x + 2

Step-by-step explanation:

The equation for two points on a line is generated from the straight line equation y = mx + b ---------------- eqn (i)

where m, the slope = (y2 - y1) / (x2 - x1)

therefore for (0,2) and (1,5) m = (5 - 2)/(1 - 0) = 3

This implies that eqn (i) can be rewritten as:

y = 3x + b ------------------- eqn (ii)

pickintg the point (0,2) and substituting into eqn (ii)

2 = 3(0) + b

this implies that b = 2

for confirmation with (1,5)

5 = 3(1) + b

b = 5 - 3 = 2

hence m = 3, b = 2

the equation is y = 3x + 2

6 0

3 years ago

Use substitution to solve the following system of linear equations and fill in the following blanks:

marissa [1.9K]

Answer:

$x=-4$

$y=3$

$z=-5$

Step-by-step explanation:

Given:

$x+y+z=-6$

$x-6y-7z=-29$

$-7y-5z=4$

Solve for $x$ in the 1st equation:

$x+y+z=-6$

$x+y=-z-6$

$x=-y-z-6$

Substitute the value of $x$ into the 2nd equation and solve for $z$ :

$x-6y-7z=-29$

$(-y-z-6)-6y-7=-29$

$-7y-z-13=-29$

$-7y-z=-16$

$-z=-16+7y$

$z=16-7y$

Substitute the value of $z$ into the 3rd equation and solve for $y$ :

$-7y-5z=4$

$-7y-5(16-7y)=4$

$-7y-80+35y=4$

$28y-80=4$

$28y=84$

$y=3$

Plug $y=3$ into the solved expression for $z$ and evaluate to solve for $z$ :

$z=16-7(3)$

$z=16-21$

$z=-5$

Plug $z=-5$ into the solved expression for $x$ and evaluate to solve for $x$ :

$x=-(3)-(-5)-6$

$x=-3+5-6$

$x=2-6$

$x=-4$

Therefore:

$x=-4$

$y=3$

$z=-5$

6 0

3 years ago