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3 years ago

How much do a dozen cookies weigh?

Mathematics

2 answers:

yaroslaw [1]3 years ago

7 0

0.43 oz

Hope this helps...

puteri [66]3 years ago

7 0

Well in reality, the average cookie weighs 0.43oz so a dozen(12) = 5.16oz

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Ralph is leasing a $32,000 car for 36 months. The terms of his lease include an 8.5% interest rate (money factor of 0.00354) and

sesenic [268]

Answer:

d. 443.73

Step-by-step explanation:

i got it right on the test

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3 years ago

The weight of an object on moon is 1/6 of its weight on Earth. If weight of an object on Earth is 18/5 kg, what would be its wei

IrinaVladis [17]

Answer:

3/5 kg

Step-by-step explanation:

The weight of an object on Moon is 6 times smaller than same on Earth.

If it weights 18/5 kg on Earth then its weight on Moon is:

18/5 * 1/6 = 3/5 kg

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2 years ago

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If line y bisects AC, AB = 4-5x, and BC =2x+25, AC

jolli1 [7]

4 - 5x = 2x + 25
4 = 7x + 25
-21 = 7x
-3 = x

4 - 5x + 2x + 25 = ac
4 - 5(-3) + 2(-3) + 25 = ac
4 - (-15) + (-6) + 25 = ac
19 + (-6) + 25 = ac
38 = ac

7 0

3 years ago

A car goes 60 miles on 2 2/3 Gallons of gas. How many miles will it go with 1 gallon of gas?

Sergio [31]

22.5 miles

You would create a proportion based on the given information, then cross multiply and solve for the number of miles 1 gallon of gas can go.

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3 years ago

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Terry and Callie do word processing. For a certain prospectus Callie can prepare it two hours faster than Terry can. If they wor

Dahasolnce [82]

Time taken by jerry alone is 10.1 hours

Time taken by callie alone is 8.1 hours

Solution:

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is $\frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }$

If they work together they can do the entire prospectus in five hours

$\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}$

On cross-multiplication we get,

$\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}$

$\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}$

On cross multiplication ,we get

$\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}$

using quadratic formula:-

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$x=\frac{12 \pm \sqrt{144-40}}{2}$

$\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}$

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

3 0

3 years ago