Answer:
Accept the claim that mean = 8.2oz.
Step-by-step explanation:
Given that a company claims that its coffee cans contain 8.2 ounces of coffee, on average.
To check this, normally large samples are drawn and sample mean is calculated
Then hypotheses created as
H0: Mean = 8.2
Ha: Mean not equals 8.2
The std deviation of sample is found out and then 95% confidence interval is calculated.
If the sample mean falls within 95% confidence interval, then we are 95% confident that for large samples, the sample mean would fall within this interval. Also the claim can be accepted.
Hence conclusion is accept null hypothesis that mean = 8.2 oz.
Answer:
The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.
Step-by-step explanation:
We have the standard deviation of the saple, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 50 - 1 = 49
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.
Answer:
k = 36 and r = 8
Step-by-step explanation:
Given that r varies directly as p and inversely as q² then the equation relating them is
r =
← k is the constant of variation
To find k use the condition r = 27 when p 3 and q = 2, thus
27 =
( multiply both sides by 4 )
108 = 3k ( divide both sides by 3 )
k = 36
r =
← equation of variation
When p = 2 and q = 3, then
r =
=
= 8
There's a bit of ambiguity in your question...
We know that
, which means
.
I see three possible interpretations:
• If
, then

• If
, then

• If
, then
![f(7)=-15=\sqrt[k]{2+7}\implies-15=9^{1/k}\implies\dfrac1k=\log_9(-15)](https://tex.z-dn.net/?f=f%287%29%3D-15%3D%5Csqrt%5Bk%5D%7B2%2B7%7D%5Cimplies-15%3D9%5E%7B1%2Fk%7D%5Cimplies%5Cdfrac1k%3D%5Clog_9%28-15%29)
which has no real-valued solution.
I suspect the second interpretation is what you meant to write.
Answer:
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