I believe there is only one outlier (shown in this picture) mostly because it is the farthest from this dotted mess
See the attached picture:
to the nearest tenth = 9.2
The speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
Let the speed of one bicyclist=x mph
Let the speed of the other bicyclist=(x+3) mph
Hence:
Speed of one bicyclist:
3x+3(x+3)+2=98
3x+3x+9+2=98
6x=87
Divide both side by 6x
x=87/6
x=14.5 mph
Speed of the other bicyclist:
x+3 mph
14.5 mph+3 mph
=17.5 mph
Inconclusion the speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.
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The question is not clear, but it is possible to obtain distance, s, from the given function. This, I would show.
Answer:
s = 17 units
Step-by-step explanation:
Given f(t) = t³ - 8t² + 27t
Differentiating f(t), we have
f'(t) = 3t² - 16 t + 27
At t = 0
f'(t) = 27
This is the required obtainaible distance, s.
Answer
Find out the how much did each student recieve .
To prove
Let us assume that each student earned in the bake sell be x .
As given
Three students earned $48.76 at the bake sell.
The students split the earnings evenly i.e earning is divided into three equal parts .
Than the equation becomes
Solving the above
x = $16.25(approx)
Therefore the each student recieve $16.25(approx) .
Hence proved
