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3 years ago

99 POINTS

Physics

2 answers:

sdas [7]3 years ago

7 0

Hello!

For big answers like this I write it down on a piece of paper but I don't know how to put it into my answer :/

The average velocity of the squirrel is 2.4 m/s.

I hope it helps!

tensa zangetsu [6.8K]3 years ago

3 0

Since the acorn is thrown horizontally, the initial vertical velocity is 0 m/s. Let’s use the following equation to determine the time to fall 10 meters.

d = vi * t + ½ * a * t^2, vi = 0, a = 9.8 
10 = 4.9 * t^2 
t = √(10/4.9) 
This is approximately 1.43 seconds. Let’s use the following equation to determine the horizontal distance it moves. 

d = v * t = 1.1 * √(10/4.9) 
This is approximately 1.57 meters. To determine the horizontal distance between the acorn and squirrel, subtract this distance from 5 meters. 

d = 5 – 1.1 * √(10/4.9) 

This is approximately 3.83 meters. To catch the acorn, the squirrel must move this distance in the same time as the acorn falls 10 meters. 

Average velocity = ([5 – 1.1 * √(10/4.9] ÷ √(10/4.9) = 2.4 m/s 

I hope this helps you to understand how to solve this type of problem.

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GuDViN [60]

I believe this is electron degeneracy, because the star is essentially having too many reactions too fast and collapses in on itself eventually.

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4 years ago

A man and his dog are “walking” on flat Street. He is pulling on his stubborn dog with a force of 70 N Directed at a 30° angle f

Delvig [45]

Answer:

X component of force is 60.62 N.

Y component of force is 35 N.

Force of gravity on the dog is 245 N.

Magnitude of normal force is 210 N.

Explanation:

Given:

Force of pull is, $F=70\ N$

Mass of the dog is, $m=25\ kg$

Angle of inclination is, $\theta =30$ °

Acceleration due to gravity is, $g=9.8\ m/s^2$

The free body diagram of the dog is shown below.

The X and Y components of force of pull is given as:

$F_X=F\cos \theta=(70)\cos (30)=60.62\ N\\F_Y=F\sin \theta=(70)\sin(30)=35\ N$

Therefore, the X and Y components of the force are 60.62 N and 35 N respectively.

Force of gravity on the dog is the product of its mass and acceleration due to gravity. Thus,

$F_g=mg=25\times 9.8=245\ N$

Therefore, the force of gravity on the dog is 245 N.

Now, consider the motion in the vertical direction of the dog. As there is no motion in the vertical direction, the net force along the Y direction is 0. In other words, the total Upward force is equal to the total downward force.

From the free body diagram,

$N+F_Y=mg\\N=mg-F_Y\\N=245-35=210\ N$

Therefore, the normal force acting on the dog is 210 N.

6 0

4 years ago

What is the name of the black hole in the center of the milky way

densk [106]

Answer:

Sagittarius A

Explanation:

The center of the milky way has a big giant hole known as "Sagittarius A". The size is 4 million times bigger than the sun.

4 0

3 years ago

[Assume g = 10m/s?] If a girl is running along a straight road with a uniform velocity 1.5 m/s, find her acceleration. (Ans: 0)

DerKrebs [107]

Answer:

Her acceleration is 0 m/s²

Explanation:

We note that the motion of the girl is on a straight road, therefore;

The vertical acceleration (e.g. due to gravity, g) on the horizontal motion = 0

The horizontal acceleration, a = (Change in velocity, Δv)/(Change in time, Δt)

For uniform velocity, the change in velocity, Δv = 0

Therefore, fore any change in time, Δt, we have;

a = Δv/Δt

Her acceleration, a = 0/Δt = 0

Her acceleration, a = 0 m/s²

7 0

3 years ago

I need help with one - seven

vesna_86 [32]

Answer:

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Explanation:

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6 0

3 years ago

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99 POINTS