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Mandarinka [93]
3 years ago
7

A lamp draws a current of 0.50 A when it is connected to a 120 V source? What is the resistance of the lamp?

Physics
2 answers:
emmainna [20.7K]3 years ago
8 0
Given,
Current (I) = 0.50A
Voltage (V) = 120 volts
Resistance (R) =?
We know that:-
Voltage (V) = Current (I) x Resistance (R)
→Resistance (R) = Voltage (V) / Current (I)
= 120/0.50
= 24Ω
∴ Resistance (R) = 24Ω
Ronch [10]3 years ago
3 0

For this case we have that by definition, Ohm's Law states that:

V = I * R

Where:

V: It's the voltage

I: It's the current

R: It's the resistance

According to the data we have to:

I = 0.50A\\V = 120V

Clearing the resistance formula we have:

R = \frac {V} {I}\\R = \frac {120} {0.50}\\R = 240

So, the resistance is 240 ohms!

Answer:

240Ω

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Answer:

The  kinetic energy is KE  =  7.59  *10^{10} \  J

Explanation:

From the question we are told that

       The  radius of the orbit is  r =  2.3 *10^{4} \ km  = 2.3  *10^{7} \ m

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The kinetic energy of the satellite is mathematically represented as

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where v is the speed of the satellite which is mathematically represented as

     v  = \sqrt{\frac{G  M}{r^2} }

=>  v^2  =  \frac{GM }{r}

substituting this into the equation

      KE  =  \frac{ 1}{2} *\frac{GMm}{r}

Now the gravitational force of the planet is mathematically represented as

      F_g  = \frac{GMm}{r^2}

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 Now looking at the formula for KE we see that we can represent it as

     KE  =  \frac{ 1}{2} *[\frac{GMm}{r^2}] * r

=>    KE  =  \frac{ 1}{2} *F_g * r

substituting values

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