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Mandarinka [93]
3 years ago
7

A lamp draws a current of 0.50 A when it is connected to a 120 V source? What is the resistance of the lamp?

Physics
2 answers:
emmainna [20.7K]3 years ago
8 0
Given,
Current (I) = 0.50A
Voltage (V) = 120 volts
Resistance (R) =?
We know that:-
Voltage (V) = Current (I) x Resistance (R)
→Resistance (R) = Voltage (V) / Current (I)
= 120/0.50
= 24Ω
∴ Resistance (R) = 24Ω
Ronch [10]3 years ago
3 0

For this case we have that by definition, Ohm's Law states that:

V = I * R

Where:

V: It's the voltage

I: It's the current

R: It's the resistance

According to the data we have to:

I = 0.50A\\V = 120V

Clearing the resistance formula we have:

R = \frac {V} {I}\\R = \frac {120} {0.50}\\R = 240

So, the resistance is 240 ohms!

Answer:

240Ω

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Answer:

The answer is B.

Explanation:

Given that the <em>current </em>(Ampere) in a series circuit is same so we can ignore it. We can assume that the total voltage is 60V and all the 3 resistance are different, 20Ω, 40Ω and 60Ω. So first, we have to find the total resistance by adding :

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Next, we have to find out that 1Ω is equal to how many voltage by dividing :

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A single-turn circular loop of radius 6 cm is to produce a field at its center that will just cancel the earth's field of magnit
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Answer:

The current is  I  = 6.68 \  A

Explanation:

From the question we are told that  

     The radius of the loop is  r =  6 \ cm  = 0.06 \ m

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Now for the earth's magnetic field to be canceled out the magnetic field generated by the loop must be equal to the magnetic field out the earth

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=>     I  =  \frac{2 *  0.06 *  0.7 *10^{-4}}{ 4\pi * 10^{-7} * 1}

       I  = 6.68 \  A

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