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earnstyle [38]
3 years ago
6

Two technicians are discussing hydraulics. Technician A says that if pistons of the same size are used, motion and force can be

increased or decreased. Technician B says that if a small piston acts upon a larger piston, the force of the larger piston will increase, but the distance it travels will decrease. Who is correct? A. Technician B only B. Technician A only C. Both Technician A and B D. Neither Technician A nor B
Physics
1 answer:
Strike441 [17]3 years ago
6 0

the correct option is A. Only technician B is correct.

Hydraulics works on the pascal law, which states that in a direction the hydro static fluid pressure remains constant.

Px=Py=Pz

Since small piston has small area compare to the large piston

Pbig=Psmall

Fbig/Abig=Fsm/Asm

Fbig=\frac{Abig}{Asmall}*Fsmall

thus the force on the large piston will increase, but it travel small distance.

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Un cuerpo de 480 g de masa es atraído con una fuerza de 3.9 E-6 N por otro cuerpo de 196 g de masa. Calcula la distancia a la qu
Soloha48 [4]

Answer:

La distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

Explanation:

Asumamos que ambos cuerpos son partículas, la fuerza de atracción (F), en newtons, entre ambos cuerpos se define mediante la Ley de Newton de la Gravitación Universal, cuya ecuación es:

F = G \cdot \frac{m_{1}\cdot m_{2}}{r^{2}} (1)

Donde:

G - Constante de la gravitación universal, en metros cúbicos por kilogramo-segundo cuadrado.

m_{1}, m_{2} - Masas de los cuerpos, en kilogramos.

r - Distancia entre los cuerpos, en metros.

Si sabemos que G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, m_{1} = 0.48\,kg, m_{2} = 0.196\,kg y F = 3.9\times 10^{-6}\,N, entonces la distancia entre los dos cuerpos es:

r = \sqrt{\frac{G\cdot m_{1}\cdot m_{2}}{F} }

r \approx 1.269\times 10^{-3}\,m

Es decir, la distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

5 0
3 years ago
A crate of oranges is shoved across a grocery store floor with a force of 100 N for a distance of 1 meter. The crate travels an
navik [9.2K]

The statements that are true are;

  • the magnitude of work done by frictional forces on the crate is 100 J
  • the magnitude of work done by the applied force on the crate is 100 J
<h3>What is work done?</h3>

Work is said to be done when te force applied travels a distance in the direction of the force. Now we can see that when the force is applied by shoving the crate, work is done, an additional work is done by friction to bring the crate to a stop.

Hence, the following are true;

  • the magnitude of work done by frictional forces on the crate is 100 J
  • the magnitude of work done by the applied force on the crate is 100 J

Learn more about work: brainly.com/question/18094932?

4 0
2 years ago
A boy takes hold of a rope to pull a wagon (m = 50 kg) on a surface with a static coefficient of friction μS = 0.25. Calculate t
vivado [14]

Answer:

<em>The force that would be applied on the rope just to start moving the wagon is 122 N</em>

Explanation:

Frictional force opposes motion between two surfaces in contact. It is the force that must be applied before a body starts to move. Static friction  opposes the motion of two bodies that are in contact but are not moving. The magnitude of static friction to overcome for the body to move  can be calculated using equation 1.

F = μ x mg .............................. 1

where F is the frictional force;

          μ is the coefficient of friction ( μs, in this case, static friction);

          m  is mass of the object and;

          g is the acceleration due to gravity( a constant equal to 9.81 m/s^{2})

from the equation we are provide with;

       μs  = 0.25

       m = 50 kg

       g =  9.81 m/s^{2}

      F =?

Using equation 1

F = 0.25 x 50 kg x  9.81 m/s^{2}

F = 122.63 N  

<em>Therefore a force of 122 N must be applied to the rope just to start the wagon.</em>

6 0
4 years ago
Read 2 more answers
Which elements are not noble gases?
Ivan
Helium lithium and calcium
3 0
3 years ago
Read 2 more answers
Determine the speed of sound in air at 300 K. Also determine the Mach number of an aircraft moving in the air at a velocity of 3
amm1812

Answer:

c_3_0_0_K=347.19m/s

M=0.864

Explanation:

The speed of sound in the air increases 0.6 m / s for every 1 ° C increase in temperature.  An approximate speed can be calculated using the following empirical formula:

c=331.5+0.6\vartheta

Where:

\vartheta=T-273.15K\\\\

A more exact equation, usually referred to as adiabatic velocity of sound, is given by the following formula:

c=\sqrt{k*R*T}

Where:

R= Gas\hspace{3}constant\hspace{3}of\hspace{3}air=0.287kJ/kg*K=287J/kg*K\\k=Specific\hspace{3}heat\hspace{3}ratio=1.4\\T=Temperature=300K

Hence:

c=\sqrt{(287)*(1.4)*(300)} =347.1887095\approx347.19m/s

Now, the Mach number at which an aircraft is flying can be calculated by:

M=\frac{u}{c}

Where:

u= Velocity\hspace{3}of\hspace{3}the\hspace{3}moving\hspace{3}aircraft\\c= Speed\hspace{3}of\hspace{3}sound\hspace{3}at\hspace{3}the\hspace{3}given \hspace{3}altitude

Therefore:

M=\frac{300}{347.19} =0.8640833984\approx0.864

5 0
4 years ago
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