Answer:
Explanation:
The pressure of a liquid is the rate of the force applied by the liquid on a surface per unit area of the surface.
i.e P = 
where P is the pressure, F is the force and A is the area.
The depth of the liquid determines its pressure at a definite lower point. As the pressure of a liquid at the bottom of a its container is greater than the pressure at the top of the liquid.
Thus,
P = σhg
where P is the pressure, σ is the density of the liquid, h is the height and g is the force of gravity.
It is measured in Pascals or N
.
The pressure of liquid has a lot of applications, viz: siphon, force pump, lift pump etc.
We first calculate the acceleration on the ball using:
2as = v² - u²; u = 0 because ball is initially at rest
a = (36)²/(2 x 0.35)
a = 1850 m/s²
F = ma
F = 0.058 x 1850
= 107.3 Newtons
The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)
<u>Explanation:</u>
Given data
Amplitude 0.02 m , Frequency= 440 Hz ,Speed = 330 m/s
The equation format is written as,
y = A sin ( k x – ω t)
We need the value of A, k, x -ω t
<u>1. Find the k value</u>
v = f ×λ
330 = 440×λ
k = 2π×λ
k = 880 π /330 m-1
440 ×2π = w
<u>2. Find the ω value</u>
f×2π =ω
ω
= 880 π s-1
<u>3. Find the A value</u>
we get A value from the given data
A = 0.02 m
By the formula,
y = A sin ( k x – ω t)
Substitute the values we get the equation,
y = 0.02 sin (880π/330 x – 880 πt)
The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)
Answer:
A. Area under force-time graph & Area under force-displacement graph
Explanation:
To find the impulse or work done the area under force-time graph and area under force-displacement graph will give us these respective values.
Impulse = Force x time
Work done = Force x displacement
When we plot a graph of force and time, the area under it is the impulse.
When a graph of force and displacement is plotted, the area under is the work done.
