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3 years ago

HELP BRIANLIEST TO BEST ANSWER

Mathematics

2 answers:

elixir [45]3 years ago

8 0

Answer:

false they are measuring the amount the sold

AlekseyPX3 years ago

4 0

Answer:

If anything, I think the answer is true. That is about 30 days, and that is an independent variable to me.

Step-by-step explanation:

You might be interested in

Can somebody please help me with this problem??? I can't figure it out...

Lorico [155]

We can use the Pythagorean theorem to solve. (a² + b² = c²)

Fill in with what we know → 6² + b² = 11²

Simplify → 36 + b² = 121

Subtract 36 to both sides → 36 - 36 + b² = 121 - 36

Simplify → b² = 85

Take the root of both sides → √b² = √85

Simplify → b = 9.2195...

Round if necessary → 9.2195 = 9.22

Hence, b equals 9.2195.. (unrounded) or 9.22 (rounded).

Best of Luck!

7 0

3 years ago

The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St

AysviL [449]

Answer:

a) 0.0668 = 6.68% probability that a domestic airfare is $550 or more

b) 0.1093 = 10.93% probability than a domestic airfare is $250 or less

c) 0.6313 = 63.13% probability that a domestic airfare is between $300 and $500

d) The cost for the 3% highest domestic airfares are $592 and higher.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 385, \sigma = 110$

a. What is the probability that a domestic airfare is $550 or more (to 4 decimals)?

This is 1 subtracted by the pvalue of Z when X = 550. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{550 - 385}{110}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that a domestic airfare is $550 or more

b. What is the probability than a domestic airfare is $250 or less (to 4 decimals)?

This is the pvalue of Z when X = 250. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{250 - 385}{110}$

$Z = -1.23$

$Z = -1.23$ has a pvalue of 0.1093

0.1093 = 10.93% probability than a domestic airfare is $250 or less

c. What if the probability that a domestic airfare is between $300 and $500 (to 4 decimals)?

This is the pvalue of Z when X = 500 subtracted by the pvalue of Z when X = 300. So

X = 500

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{500 - 385}{110}$

$Z = 1.045$

$Z = 1.045$ has a pvalue of 0.8519

X = 300

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{300 - 385}{110}$

$Z = -0.77$

$Z = -0.77$ has a pvalue of 0.2206

0.8519 - 0.2206 = 0.6313

0.6313 = 63.13% probability that a domestic airfare is between $300 and $500

d. What is the cost for the 3% highest domestic airfares?

At least the 97th percentile, so at least X when Z has a pvalue of 0.97. So X when Z = 1.88.

$Z = \frac{X - \mu}{\sigma}$

$1.88 = \frac{X - 385}{110}$

$X - 385 = 1.88*110$

$X = 592$

The cost for the 3% highest domestic airfares are $592 and higher.

7 0

3 years ago

Solve for x in the following equation: ax+5x-4=10

andre [41]

Factor in "x" the expression:

$ax+5x-4=10\\
\\
(a+5)x-4=10\\
\\
(a+5)x=10+4\\
\\
(a+5)x=14\\
\\
\boxed{x=\frac{14}{a+5}}$

4 0

3 years ago

I kneed help

bonufazy [111]

Answer:

thats pretty easy its A

Step-by-step explanation:

cuz its talking about candidates

6 0

3 years ago

Read 2 more answers

Discs of a radius 4cm are cut from a rectangular plastic sheet of length 84cm and width 24 cm

Aleonysh [2.5K]

Answer: 40

Step-by-step explanation:

Given

Radius of disc $r=4\ cm$

The dimension of the sheet is $84\times 24\ cm^2$

Area of a single disc

$\Rightarrow a=\pi r^2=\frac{22}{7}\times 4^2\\\\\Rightarrow a=\frac{352}{7}\ cm^2$

Area of sheet

$\Rightarrow A=84\times 24=2016\ cm^2$

No. of discs that can be cut off the sheet are

$\Rightarrow n=\dfrac{A}{a}=\dfrac{2016}{\frac{352}{7}}=\dfrac{2016\times7}{352}\\\Rightarrow n\approx 40$

The total area of the disc is

$\Rightarrow na=40\times\frac{352}{7}=2011.428\ cm^2$

Sheet wasted

$\Rightarrow A-na=2016-2011.428=4.57\ cm^2$

7 0

3 years ago