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DochEvi [55]
3 years ago
9

How are the values of the 3's in 33,000 related

Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0
In which place? Of the value one tens hunderd thousnd
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What is the sum of all integers x that satisfy 1 < (pi -1 )x < 10?
DedPeter [7]

Answer:

10

Step-by-step explanation:

pi is 3.14...

pi - 1 is 2.14...

question becomes 1<2.14x and 2.14x < 10

1/2.14 < x, 0.46... < x

x < 10/2.14, x < 4.67...

combining

0.46< x < 4.67

x can be 1, 2, 3, 4

3 0
3 years ago
Read 2 more answers
If x=-5 what is the value of x^2-1/x+1? A. 6 b. -4 c. 4 d. 5 4/5 e. 19 <br> need answers asap
xxTIMURxx [149]

Answer:

The answer is -6 but its not in the option

Step-by-step explanation:

\frac{ {x}^{2} - 1 }{ x  + 1}

Let x = -5

[(-5)²-1]/(-5+1)

= (25-1)/(-4)

= 24/-4

= -6

4 0
3 years ago
Create an equivalent system of equations using the sum of the system and the first equation. x + 4y = 8 4x + y = 2
qaws [65]

Answer:

Equivalent systems of equations review

Step-by-step explanation:

We're given two systems of equations and asked if they're equivalent.

x + 4y = 8 (1)

4x + y = 2 (2)

Interestingly, if we sum the equations in System A, we get:

x + 4y = 8 \\4x + y = 2 \\

5x+5y=10

Replacing the first equation in System A with this new equation, we get a system that's equivalent to System A:

5x+5y=10

4x + y = 2

This is System B, which means that System A is equivalent to System B.

5 0
3 years ago
Determine the standard deviation of the data below. (1, 2, 3, 4, 5)
Burka [1]

Answer:

\sqrt{2} or 1.414

Step-by-step explanation:

1) Find the mean. 1+2+3+4+5 = 15. 15/5= 3

2) For each data point, find the square of its distance to the mean. (4, 1, 0, 1, 4)

3) Sum the values from Step 2. 10

4) Divide by the number of data points. 10/5= 2

5) Take the square root. \sqrt{2}

4 0
3 years ago
CAN SOMEONE PLEASE HELP ME
Anit [1.1K]

Answer:

40

Step-by-step explanation:

80 divided by 2 is 40 and the formula is L times W times Height and the height is 2 so the base is 40 B times H

It's 40

4 0
3 years ago
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